Cube inscribed in a hemi-spherical shape












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What should be the approach to determine the distance? It seems that we need to form a Pythagorean triangle for this one. If it was a cube inside a sphere we could have easily said that the diameter of the sphere will be equal to the diagonal of the cube. But I am not able to visualize this problem.



enter image description here










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    Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
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    – dantopa
    Dec 27 '18 at 19:21






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    $begingroup$
    Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
    $endgroup$
    – achille hui
    Dec 27 '18 at 19:30


















0












$begingroup$


What should be the approach to determine the distance? It seems that we need to form a Pythagorean triangle for this one. If it was a cube inside a sphere we could have easily said that the diameter of the sphere will be equal to the diagonal of the cube. But I am not able to visualize this problem.



enter image description here










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
    $endgroup$
    – dantopa
    Dec 27 '18 at 19:21






  • 1




    $begingroup$
    Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
    $endgroup$
    – achille hui
    Dec 27 '18 at 19:30
















0












0








0





$begingroup$


What should be the approach to determine the distance? It seems that we need to form a Pythagorean triangle for this one. If it was a cube inside a sphere we could have easily said that the diameter of the sphere will be equal to the diagonal of the cube. But I am not able to visualize this problem.



enter image description here










share|cite|improve this question











$endgroup$




What should be the approach to determine the distance? It seems that we need to form a Pythagorean triangle for this one. If it was a cube inside a sphere we could have easily said that the diameter of the sphere will be equal to the diagonal of the cube. But I am not able to visualize this problem.



enter image description here







geometry






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edited Dec 27 '18 at 19:22









dantopa

6,68442245




6,68442245










asked Dec 27 '18 at 19:15









Ritwik BhattacharyyaRitwik Bhattacharyya

1




1








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    $begingroup$
    Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
    $endgroup$
    – dantopa
    Dec 27 '18 at 19:21






  • 1




    $begingroup$
    Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
    $endgroup$
    – achille hui
    Dec 27 '18 at 19:30
















  • 1




    $begingroup$
    Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
    $endgroup$
    – dantopa
    Dec 27 '18 at 19:21






  • 1




    $begingroup$
    Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
    $endgroup$
    – achille hui
    Dec 27 '18 at 19:30










1




1




$begingroup$
Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
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– dantopa
Dec 27 '18 at 19:21




$begingroup$
Welcome the Mathematics Stack Exchange. A quick tour of the site (math.stackexchange.com/tour) will help you get the most of your time here. For typesetting your equations, please use MathJax: math.meta.stackexchange.com/questions/5020/…
$endgroup$
– dantopa
Dec 27 '18 at 19:21




1




1




$begingroup$
Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
$endgroup$
– achille hui
Dec 27 '18 at 19:30






$begingroup$
Hint: Let $O$ be the common center of the base and the hemisphere and $C$ be the vertex of cube above $B$. What is the relationship between $|AB|$ and $|OC|$?
$endgroup$
– achille hui
Dec 27 '18 at 19:30












2 Answers
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The distance from a corner at the base to the center of the top is the same as the distance from the center of the base to a corner at the top. This length is the radius of the hemisphere: $10$m






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    $begingroup$

    Let $O$ be a center of our sphere and $K$ be a top left vertex of the cuboid.



    Now, easy to see that $OKAB$ is a parallelogram ($AK||OB$ and $AK=OB$), which gives $$AB=OK=frac{20}{2}=10.$$






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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

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      active

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      active

      oldest

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      1












      $begingroup$

      The distance from a corner at the base to the center of the top is the same as the distance from the center of the base to a corner at the top. This length is the radius of the hemisphere: $10$m






      share|cite|improve this answer









      $endgroup$


















        1












        $begingroup$

        The distance from a corner at the base to the center of the top is the same as the distance from the center of the base to a corner at the top. This length is the radius of the hemisphere: $10$m






        share|cite|improve this answer









        $endgroup$
















          1












          1








          1





          $begingroup$

          The distance from a corner at the base to the center of the top is the same as the distance from the center of the base to a corner at the top. This length is the radius of the hemisphere: $10$m






          share|cite|improve this answer









          $endgroup$



          The distance from a corner at the base to the center of the top is the same as the distance from the center of the base to a corner at the top. This length is the radius of the hemisphere: $10$m







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 27 '18 at 19:30









          Daniel MathiasDaniel Mathias

          1,40518




          1,40518























              0












              $begingroup$

              Let $O$ be a center of our sphere and $K$ be a top left vertex of the cuboid.



              Now, easy to see that $OKAB$ is a parallelogram ($AK||OB$ and $AK=OB$), which gives $$AB=OK=frac{20}{2}=10.$$






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                Let $O$ be a center of our sphere and $K$ be a top left vertex of the cuboid.



                Now, easy to see that $OKAB$ is a parallelogram ($AK||OB$ and $AK=OB$), which gives $$AB=OK=frac{20}{2}=10.$$






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  Let $O$ be a center of our sphere and $K$ be a top left vertex of the cuboid.



                  Now, easy to see that $OKAB$ is a parallelogram ($AK||OB$ and $AK=OB$), which gives $$AB=OK=frac{20}{2}=10.$$






                  share|cite|improve this answer









                  $endgroup$



                  Let $O$ be a center of our sphere and $K$ be a top left vertex of the cuboid.



                  Now, easy to see that $OKAB$ is a parallelogram ($AK||OB$ and $AK=OB$), which gives $$AB=OK=frac{20}{2}=10.$$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Dec 30 '18 at 19:33









                  Michael RozenbergMichael Rozenberg

                  110k1896201




                  110k1896201






























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