I need to group by and get the rank in python












0















I have a dataframe , refer below code to generate it :



     df = pd.DataFrame({'customer': [1,2,1,3,1,2,3], 
"group_code": ['111', '111', '222', '111', '111', '111', '333'],
"ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
"amount": [100, 200, 140, 400, 225, 125, 600],
"card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})


Suppose i wanted to group it by card and wanted to know for each card which group code has highest amount ? and create a new dataframe with that card number and group code with highest amount.



Kindly help at the earliest.










share|improve this question



























    0















    I have a dataframe , refer below code to generate it :



         df = pd.DataFrame({'customer': [1,2,1,3,1,2,3], 
    "group_code": ['111', '111', '222', '111', '111', '111', '333'],
    "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
    "amount": [100, 200, 140, 400, 225, 125, 600],
    "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})


    Suppose i wanted to group it by card and wanted to know for each card which group code has highest amount ? and create a new dataframe with that card number and group code with highest amount.



    Kindly help at the earliest.










    share|improve this question

























      0












      0








      0








      I have a dataframe , refer below code to generate it :



           df = pd.DataFrame({'customer': [1,2,1,3,1,2,3], 
      "group_code": ['111', '111', '222', '111', '111', '111', '333'],
      "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
      "amount": [100, 200, 140, 400, 225, 125, 600],
      "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})


      Suppose i wanted to group it by card and wanted to know for each card which group code has highest amount ? and create a new dataframe with that card number and group code with highest amount.



      Kindly help at the earliest.










      share|improve this question














      I have a dataframe , refer below code to generate it :



           df = pd.DataFrame({'customer': [1,2,1,3,1,2,3], 
      "group_code": ['111', '111', '222', '111', '111', '111', '333'],
      "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
      "amount": [100, 200, 140, 400, 225, 125, 600],
      "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})


      Suppose i wanted to group it by card and wanted to know for each card which group code has highest amount ? and create a new dataframe with that card number and group code with highest amount.



      Kindly help at the earliest.







      python pandas-groupby






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 21 '18 at 10:38









      SheriffSheriff

      458




      458
























          1 Answer
          1






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          2














          You could do:



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          mask = df.groupby('card')['amount'].transform(max) == df['amount']

          result = df[mask][['card', 'group_code', 'amount']]

          print(result)


          Output



            card group_code  amount
          1 YYY 111 200
          6 XXX 333 600


          UPDATE



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          agg = df.groupby(['card', 'group_code']).agg({'amount':'sum'}).reset_index()
          mask = agg.groupby('card')['amount'].transform(max) == agg['amount']
          result = agg[mask]
          print(result)


          Output



            card group_code  amount
          0 XXX 111 725
          2 YYY 111 325





          share|improve this answer


























          • Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

            – Sheriff
            Nov 21 '18 at 11:01











          • @Sheriff see the update.

            – Daniel Mesejo
            Nov 21 '18 at 11:14











          • Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

            – Sheriff
            Nov 21 '18 at 12:48











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          You could do:



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          mask = df.groupby('card')['amount'].transform(max) == df['amount']

          result = df[mask][['card', 'group_code', 'amount']]

          print(result)


          Output



            card group_code  amount
          1 YYY 111 200
          6 XXX 333 600


          UPDATE



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          agg = df.groupby(['card', 'group_code']).agg({'amount':'sum'}).reset_index()
          mask = agg.groupby('card')['amount'].transform(max) == agg['amount']
          result = agg[mask]
          print(result)


          Output



            card group_code  amount
          0 XXX 111 725
          2 YYY 111 325





          share|improve this answer


























          • Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

            – Sheriff
            Nov 21 '18 at 11:01











          • @Sheriff see the update.

            – Daniel Mesejo
            Nov 21 '18 at 11:14











          • Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

            – Sheriff
            Nov 21 '18 at 12:48
















          2














          You could do:



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          mask = df.groupby('card')['amount'].transform(max) == df['amount']

          result = df[mask][['card', 'group_code', 'amount']]

          print(result)


          Output



            card group_code  amount
          1 YYY 111 200
          6 XXX 333 600


          UPDATE



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          agg = df.groupby(['card', 'group_code']).agg({'amount':'sum'}).reset_index()
          mask = agg.groupby('card')['amount'].transform(max) == agg['amount']
          result = agg[mask]
          print(result)


          Output



            card group_code  amount
          0 XXX 111 725
          2 YYY 111 325





          share|improve this answer


























          • Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

            – Sheriff
            Nov 21 '18 at 11:01











          • @Sheriff see the update.

            – Daniel Mesejo
            Nov 21 '18 at 11:14











          • Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

            – Sheriff
            Nov 21 '18 at 12:48














          2












          2








          2







          You could do:



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          mask = df.groupby('card')['amount'].transform(max) == df['amount']

          result = df[mask][['card', 'group_code', 'amount']]

          print(result)


          Output



            card group_code  amount
          1 YYY 111 200
          6 XXX 333 600


          UPDATE



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          agg = df.groupby(['card', 'group_code']).agg({'amount':'sum'}).reset_index()
          mask = agg.groupby('card')['amount'].transform(max) == agg['amount']
          result = agg[mask]
          print(result)


          Output



            card group_code  amount
          0 XXX 111 725
          2 YYY 111 325





          share|improve this answer















          You could do:



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          mask = df.groupby('card')['amount'].transform(max) == df['amount']

          result = df[mask][['card', 'group_code', 'amount']]

          print(result)


          Output



            card group_code  amount
          1 YYY 111 200
          6 XXX 333 600


          UPDATE



          import pandas as pd

          df = pd.DataFrame({'customer': [1,2,1,3,1,2,3],
          "group_code": ['111', '111', '222', '111', '111', '111', '333'],
          "ind_code": ['A', 'B', 'AA', 'A', 'AAA', 'C', 'BBB'],
          "amount": [100, 200, 140, 400, 225, 125, 600],
          "card": ['XXX', 'YYY', 'YYY', 'XXX', 'XXX', 'YYY', 'XXX']})
          agg = df.groupby(['card', 'group_code']).agg({'amount':'sum'}).reset_index()
          mask = agg.groupby('card')['amount'].transform(max) == agg['amount']
          result = agg[mask]
          print(result)


          Output



            card group_code  amount
          0 XXX 111 725
          2 YYY 111 325






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 21 '18 at 11:14

























          answered Nov 21 '18 at 10:45









          Daniel MesejoDaniel Mesejo

          18.7k21433




          18.7k21433













          • Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

            – Sheriff
            Nov 21 '18 at 11:01











          • @Sheriff see the update.

            – Daniel Mesejo
            Nov 21 '18 at 11:14











          • Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

            – Sheriff
            Nov 21 '18 at 12:48



















          • Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

            – Sheriff
            Nov 21 '18 at 11:01











          • @Sheriff see the update.

            – Daniel Mesejo
            Nov 21 '18 at 11:14











          • Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

            – Sheriff
            Nov 21 '18 at 12:48

















          Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

          – Sheriff
          Nov 21 '18 at 11:01





          Thanks for helping. But i think we are getting it wrong. In the DF, for the card - XXX we have 2 groups - 111,333. Amount grouped by 111 : 100+400+225 = 725. Amount grouped by 333 : 600. So for card XXX it should Group code 111 and amount 725

          – Sheriff
          Nov 21 '18 at 11:01













          @Sheriff see the update.

          – Daniel Mesejo
          Nov 21 '18 at 11:14





          @Sheriff see the update.

          – Daniel Mesejo
          Nov 21 '18 at 11:14













          Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

          – Sheriff
          Nov 21 '18 at 12:48





          Great Thanks. I would require bit more here. Instead of getting the Maximum sum . In larger picture, i have a huge huge data set with 14 GB. In that case can you help me in getting the Top 3 Group codes for a particular Card based on the sum of Amount.

          – Sheriff
          Nov 21 '18 at 12:48




















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