Find, with proof, the largest natural number k such that 10^k divides 100! (one hundred factorial).












-1












$begingroup$


I was able to get to a theorem saying "that a|b if and only if for any prime in the factorization of a or b, its exponent in the factorization of a is less than or equal to its exponent in the factorization of b."



I tried to use this theorem where k <= m, k <= n, where m and n are exponents of 2 and 5, respectively, in the factorization of 100! but I was not able to work out the math so far.



Any help will be greatly appreciated!










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$endgroup$








  • 1




    $begingroup$
    Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
    $endgroup$
    – Ross Millikan
    Nov 28 '18 at 21:59
















-1












$begingroup$


I was able to get to a theorem saying "that a|b if and only if for any prime in the factorization of a or b, its exponent in the factorization of a is less than or equal to its exponent in the factorization of b."



I tried to use this theorem where k <= m, k <= n, where m and n are exponents of 2 and 5, respectively, in the factorization of 100! but I was not able to work out the math so far.



Any help will be greatly appreciated!










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
    $endgroup$
    – Ross Millikan
    Nov 28 '18 at 21:59














-1












-1








-1





$begingroup$


I was able to get to a theorem saying "that a|b if and only if for any prime in the factorization of a or b, its exponent in the factorization of a is less than or equal to its exponent in the factorization of b."



I tried to use this theorem where k <= m, k <= n, where m and n are exponents of 2 and 5, respectively, in the factorization of 100! but I was not able to work out the math so far.



Any help will be greatly appreciated!










share|cite|improve this question











$endgroup$




I was able to get to a theorem saying "that a|b if and only if for any prime in the factorization of a or b, its exponent in the factorization of a is less than or equal to its exponent in the factorization of b."



I tried to use this theorem where k <= m, k <= n, where m and n are exponents of 2 and 5, respectively, in the factorization of 100! but I was not able to work out the math so far.



Any help will be greatly appreciated!







divisibility






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edited Nov 28 '18 at 21:56









amWhy

1




1










asked Nov 28 '18 at 21:51









UMass1234UMass1234

112




112








  • 1




    $begingroup$
    Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
    $endgroup$
    – Ross Millikan
    Nov 28 '18 at 21:59














  • 1




    $begingroup$
    Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
    $endgroup$
    – Ross Millikan
    Nov 28 '18 at 21:59








1




1




$begingroup$
Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
$endgroup$
– Ross Millikan
Nov 28 '18 at 21:59




$begingroup$
Do you know Legendre's formula for the power of a prime dividing a factorial? You can also search the site for this.
$endgroup$
– Ross Millikan
Nov 28 '18 at 21:59










3 Answers
3






active

oldest

votes


















0












$begingroup$

Hint:



You use Legendre's formula: if $p$ is a prime number and $v_p(n)$ denotes the $p$-adic valuation of the natural number $n$, then



$$v_p(n!)=biggllfloorfrac npbiggrrfloor+biggllfloorfrac n{p^2}biggrrfloor+dotsm $$






share|cite|improve this answer









$endgroup$













  • $begingroup$
    thank you for the hint! Appreciate it.
    $endgroup$
    – UMass1234
    Nov 28 '18 at 22:19



















1












$begingroup$

This looks like a homework problem so I'll not give the complete answer.



Instead I invite you to ask:



How many times does the factor $5$ occur in the first 100 natural numbers? (NB remember that $25$, $50$ and $100$ are each divisible by $5^2$.) What about the factor 2?



What power of 10 can you make out of those?






share|cite|improve this answer









$endgroup$





















    0












    $begingroup$

    10 and 100 divide by 10, as do 2*5, 12*15, 22*25, 32*35, 42*45, 52*55, 62*65, 72*75, 82*85, and 92*95. Multiplying these numbers may also produce more pairs of numbers that divide by 10 when multiplied together, but there won't be any that aren't in this list.






    share|cite|improve this answer









    $endgroup$













      Your Answer





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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0












      $begingroup$

      Hint:



      You use Legendre's formula: if $p$ is a prime number and $v_p(n)$ denotes the $p$-adic valuation of the natural number $n$, then



      $$v_p(n!)=biggllfloorfrac npbiggrrfloor+biggllfloorfrac n{p^2}biggrrfloor+dotsm $$






      share|cite|improve this answer









      $endgroup$













      • $begingroup$
        thank you for the hint! Appreciate it.
        $endgroup$
        – UMass1234
        Nov 28 '18 at 22:19
















      0












      $begingroup$

      Hint:



      You use Legendre's formula: if $p$ is a prime number and $v_p(n)$ denotes the $p$-adic valuation of the natural number $n$, then



      $$v_p(n!)=biggllfloorfrac npbiggrrfloor+biggllfloorfrac n{p^2}biggrrfloor+dotsm $$






      share|cite|improve this answer









      $endgroup$













      • $begingroup$
        thank you for the hint! Appreciate it.
        $endgroup$
        – UMass1234
        Nov 28 '18 at 22:19














      0












      0








      0





      $begingroup$

      Hint:



      You use Legendre's formula: if $p$ is a prime number and $v_p(n)$ denotes the $p$-adic valuation of the natural number $n$, then



      $$v_p(n!)=biggllfloorfrac npbiggrrfloor+biggllfloorfrac n{p^2}biggrrfloor+dotsm $$






      share|cite|improve this answer









      $endgroup$



      Hint:



      You use Legendre's formula: if $p$ is a prime number and $v_p(n)$ denotes the $p$-adic valuation of the natural number $n$, then



      $$v_p(n!)=biggllfloorfrac npbiggrrfloor+biggllfloorfrac n{p^2}biggrrfloor+dotsm $$







      share|cite|improve this answer












      share|cite|improve this answer



      share|cite|improve this answer










      answered Nov 28 '18 at 22:08









      BernardBernard

      120k740113




      120k740113












      • $begingroup$
        thank you for the hint! Appreciate it.
        $endgroup$
        – UMass1234
        Nov 28 '18 at 22:19


















      • $begingroup$
        thank you for the hint! Appreciate it.
        $endgroup$
        – UMass1234
        Nov 28 '18 at 22:19
















      $begingroup$
      thank you for the hint! Appreciate it.
      $endgroup$
      – UMass1234
      Nov 28 '18 at 22:19




      $begingroup$
      thank you for the hint! Appreciate it.
      $endgroup$
      – UMass1234
      Nov 28 '18 at 22:19











      1












      $begingroup$

      This looks like a homework problem so I'll not give the complete answer.



      Instead I invite you to ask:



      How many times does the factor $5$ occur in the first 100 natural numbers? (NB remember that $25$, $50$ and $100$ are each divisible by $5^2$.) What about the factor 2?



      What power of 10 can you make out of those?






      share|cite|improve this answer









      $endgroup$


















        1












        $begingroup$

        This looks like a homework problem so I'll not give the complete answer.



        Instead I invite you to ask:



        How many times does the factor $5$ occur in the first 100 natural numbers? (NB remember that $25$, $50$ and $100$ are each divisible by $5^2$.) What about the factor 2?



        What power of 10 can you make out of those?






        share|cite|improve this answer









        $endgroup$
















          1












          1








          1





          $begingroup$

          This looks like a homework problem so I'll not give the complete answer.



          Instead I invite you to ask:



          How many times does the factor $5$ occur in the first 100 natural numbers? (NB remember that $25$, $50$ and $100$ are each divisible by $5^2$.) What about the factor 2?



          What power of 10 can you make out of those?






          share|cite|improve this answer









          $endgroup$



          This looks like a homework problem so I'll not give the complete answer.



          Instead I invite you to ask:



          How many times does the factor $5$ occur in the first 100 natural numbers? (NB remember that $25$, $50$ and $100$ are each divisible by $5^2$.) What about the factor 2?



          What power of 10 can you make out of those?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 28 '18 at 22:15









          timtfjtimtfj

          2,050419




          2,050419























              0












              $begingroup$

              10 and 100 divide by 10, as do 2*5, 12*15, 22*25, 32*35, 42*45, 52*55, 62*65, 72*75, 82*85, and 92*95. Multiplying these numbers may also produce more pairs of numbers that divide by 10 when multiplied together, but there won't be any that aren't in this list.






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                10 and 100 divide by 10, as do 2*5, 12*15, 22*25, 32*35, 42*45, 52*55, 62*65, 72*75, 82*85, and 92*95. Multiplying these numbers may also produce more pairs of numbers that divide by 10 when multiplied together, but there won't be any that aren't in this list.






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  10 and 100 divide by 10, as do 2*5, 12*15, 22*25, 32*35, 42*45, 52*55, 62*65, 72*75, 82*85, and 92*95. Multiplying these numbers may also produce more pairs of numbers that divide by 10 when multiplied together, but there won't be any that aren't in this list.






                  share|cite|improve this answer









                  $endgroup$



                  10 and 100 divide by 10, as do 2*5, 12*15, 22*25, 32*35, 42*45, 52*55, 62*65, 72*75, 82*85, and 92*95. Multiplying these numbers may also produce more pairs of numbers that divide by 10 when multiplied together, but there won't be any that aren't in this list.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Nov 28 '18 at 22:00









                  SethSeth

                  42812




                  42812






























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