Example of function $f:mathbb Rto mathbb R$ which is differentible and bijective but its inverse is not...












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Example of function $f:mathbb Rto mathbb R$ which is differentible and bijective but its inverse is not differentible.




First of all do not know is above is true as for inverse function to be not differentible , there exist some point at which $f'(x)=0$ which is not possible due to bijective ness .



Where I am missing ?



Any Help will be appereciated










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  • 3




    $begingroup$
    $f'(x)$ can be zero, e.g. $f(x)=x^3$
    $endgroup$
    – user25959
    Nov 30 '18 at 4:40










  • $begingroup$
    math.stackexchange.com/questions/2471563/…
    $endgroup$
    – d.k.o.
    Nov 30 '18 at 5:00
















0












$begingroup$



Example of function $f:mathbb Rto mathbb R$ which is differentible and bijective but its inverse is not differentible.




First of all do not know is above is true as for inverse function to be not differentible , there exist some point at which $f'(x)=0$ which is not possible due to bijective ness .



Where I am missing ?



Any Help will be appereciated










share|cite|improve this question









$endgroup$








  • 3




    $begingroup$
    $f'(x)$ can be zero, e.g. $f(x)=x^3$
    $endgroup$
    – user25959
    Nov 30 '18 at 4:40










  • $begingroup$
    math.stackexchange.com/questions/2471563/…
    $endgroup$
    – d.k.o.
    Nov 30 '18 at 5:00














0












0








0





$begingroup$



Example of function $f:mathbb Rto mathbb R$ which is differentible and bijective but its inverse is not differentible.




First of all do not know is above is true as for inverse function to be not differentible , there exist some point at which $f'(x)=0$ which is not possible due to bijective ness .



Where I am missing ?



Any Help will be appereciated










share|cite|improve this question









$endgroup$





Example of function $f:mathbb Rto mathbb R$ which is differentible and bijective but its inverse is not differentible.




First of all do not know is above is true as for inverse function to be not differentible , there exist some point at which $f'(x)=0$ which is not possible due to bijective ness .



Where I am missing ?



Any Help will be appereciated







real-analysis derivatives






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asked Nov 30 '18 at 4:38









MathLoverMathLover

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  • 3




    $begingroup$
    $f'(x)$ can be zero, e.g. $f(x)=x^3$
    $endgroup$
    – user25959
    Nov 30 '18 at 4:40










  • $begingroup$
    math.stackexchange.com/questions/2471563/…
    $endgroup$
    – d.k.o.
    Nov 30 '18 at 5:00














  • 3




    $begingroup$
    $f'(x)$ can be zero, e.g. $f(x)=x^3$
    $endgroup$
    – user25959
    Nov 30 '18 at 4:40










  • $begingroup$
    math.stackexchange.com/questions/2471563/…
    $endgroup$
    – d.k.o.
    Nov 30 '18 at 5:00








3




3




$begingroup$
$f'(x)$ can be zero, e.g. $f(x)=x^3$
$endgroup$
– user25959
Nov 30 '18 at 4:40




$begingroup$
$f'(x)$ can be zero, e.g. $f(x)=x^3$
$endgroup$
– user25959
Nov 30 '18 at 4:40












$begingroup$
math.stackexchange.com/questions/2471563/…
$endgroup$
– d.k.o.
Nov 30 '18 at 5:00




$begingroup$
math.stackexchange.com/questions/2471563/…
$endgroup$
– d.k.o.
Nov 30 '18 at 5:00










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$f'(x)$ can be zero, e.g. $f(x)=x^3$ – user25959 18 mins ago






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    $f'(x)$ can be zero, e.g. $f(x)=x^3$ – user25959 18 mins ago






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      $f'(x)$ can be zero, e.g. $f(x)=x^3$ – user25959 18 mins ago






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        $f'(x)$ can be zero, e.g. $f(x)=x^3$ – user25959 18 mins ago






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        $f'(x)$ can be zero, e.g. $f(x)=x^3$ – user25959 18 mins ago







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        answered Nov 30 '18 at 4:59


























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