Route based code splitting with react and redux











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Looking at the React doc, I implemented the route-based code splitting part in my application.



But I get an error:




TypeError: Object(...) is not a function




It seems it's coming from Redux that doesn't support function passed as components arguments and crashes when we import components with the lazy() function just like I do in my code:



const Login = lazy(() => import("../../containers/Login/Login"))


Do you have any workaround solution? I found react-loadable but that's not exactly what I want to implement.










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  • Are you exporting the Login component with export default ...?
    – Tholle
    2 days ago






  • 1




    Yes I am. export default withStyles(styles)(component)
    – Alex Mas
    2 days ago

















up vote
0
down vote

favorite












Looking at the React doc, I implemented the route-based code splitting part in my application.



But I get an error:




TypeError: Object(...) is not a function




It seems it's coming from Redux that doesn't support function passed as components arguments and crashes when we import components with the lazy() function just like I do in my code:



const Login = lazy(() => import("../../containers/Login/Login"))


Do you have any workaround solution? I found react-loadable but that's not exactly what I want to implement.










share|improve this question
























  • Are you exporting the Login component with export default ...?
    – Tholle
    2 days ago






  • 1




    Yes I am. export default withStyles(styles)(component)
    – Alex Mas
    2 days ago















up vote
0
down vote

favorite









up vote
0
down vote

favorite











Looking at the React doc, I implemented the route-based code splitting part in my application.



But I get an error:




TypeError: Object(...) is not a function




It seems it's coming from Redux that doesn't support function passed as components arguments and crashes when we import components with the lazy() function just like I do in my code:



const Login = lazy(() => import("../../containers/Login/Login"))


Do you have any workaround solution? I found react-loadable but that's not exactly what I want to implement.










share|improve this question















Looking at the React doc, I implemented the route-based code splitting part in my application.



But I get an error:




TypeError: Object(...) is not a function




It seems it's coming from Redux that doesn't support function passed as components arguments and crashes when we import components with the lazy() function just like I do in my code:



const Login = lazy(() => import("../../containers/Login/Login"))


Do you have any workaround solution? I found react-loadable but that's not exactly what I want to implement.







javascript reactjs redux code-splitting






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edited 2 days ago

























asked Nov 12 at 16:16









Alex Mas

566




566












  • Are you exporting the Login component with export default ...?
    – Tholle
    2 days ago






  • 1




    Yes I am. export default withStyles(styles)(component)
    – Alex Mas
    2 days ago




















  • Are you exporting the Login component with export default ...?
    – Tholle
    2 days ago






  • 1




    Yes I am. export default withStyles(styles)(component)
    – Alex Mas
    2 days ago


















Are you exporting the Login component with export default ...?
– Tholle
2 days ago




Are you exporting the Login component with export default ...?
– Tholle
2 days ago




1




1




Yes I am. export default withStyles(styles)(component)
– Alex Mas
2 days ago






Yes I am. export default withStyles(styles)(component)
– Alex Mas
2 days ago



















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