indent of a list to the left











up vote
0
down vote

favorite












so my previous question got answered pretty well however I have some issues. I want to move the following list to the left(minor indent):



Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$. 
Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
Now we have:
%
begin{align*}
chi{0} &= 1\
chi{1} &= a\
chi{2} &= a^2\
chi{3} &= a^3\
chi{4} &= a^4
end{align*}

with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.


I also want to put the last line of the 'code' in the same line as chi(2), as this looks more professional. also I don't want exp but the actual exponent as it looks much better.










share|improve this question









New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • I must point out, I started using latex today hence I am a novice.
    – A.E
    3 hours ago










  • I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
    – egreg
    2 hours ago










  • cheers. so to finalise, there's no need to change anything?
    – A.E
    2 hours ago










  • Just remove the blank line
    – egreg
    2 hours ago















up vote
0
down vote

favorite












so my previous question got answered pretty well however I have some issues. I want to move the following list to the left(minor indent):



Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$. 
Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
Now we have:
%
begin{align*}
chi{0} &= 1\
chi{1} &= a\
chi{2} &= a^2\
chi{3} &= a^3\
chi{4} &= a^4
end{align*}

with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.


I also want to put the last line of the 'code' in the same line as chi(2), as this looks more professional. also I don't want exp but the actual exponent as it looks much better.










share|improve this question









New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • I must point out, I started using latex today hence I am a novice.
    – A.E
    3 hours ago










  • I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
    – egreg
    2 hours ago










  • cheers. so to finalise, there's no need to change anything?
    – A.E
    2 hours ago










  • Just remove the blank line
    – egreg
    2 hours ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











so my previous question got answered pretty well however I have some issues. I want to move the following list to the left(minor indent):



Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$. 
Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
Now we have:
%
begin{align*}
chi{0} &= 1\
chi{1} &= a\
chi{2} &= a^2\
chi{3} &= a^3\
chi{4} &= a^4
end{align*}

with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.


I also want to put the last line of the 'code' in the same line as chi(2), as this looks more professional. also I don't want exp but the actual exponent as it looks much better.










share|improve this question









New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











so my previous question got answered pretty well however I have some issues. I want to move the following list to the left(minor indent):



Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$. 
Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
Now we have:
%
begin{align*}
chi{0} &= 1\
chi{1} &= a\
chi{2} &= a^2\
chi{3} &= a^3\
chi{4} &= a^4
end{align*}

with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.


I also want to put the last line of the 'code' in the same line as chi(2), as this looks more professional. also I don't want exp but the actual exponent as it looks much better.







indentation






share|improve this question









New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 2 hours ago









egreg

696k8518483111




696k8518483111






New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 3 hours ago









A.E

305




305




New contributor




A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






A.E is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • I must point out, I started using latex today hence I am a novice.
    – A.E
    3 hours ago










  • I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
    – egreg
    2 hours ago










  • cheers. so to finalise, there's no need to change anything?
    – A.E
    2 hours ago










  • Just remove the blank line
    – egreg
    2 hours ago


















  • I must point out, I started using latex today hence I am a novice.
    – A.E
    3 hours ago










  • I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
    – egreg
    2 hours ago










  • cheers. so to finalise, there's no need to change anything?
    – A.E
    2 hours ago










  • Just remove the blank line
    – egreg
    2 hours ago
















I must point out, I started using latex today hence I am a novice.
– A.E
3 hours ago




I must point out, I started using latex today hence I am a novice.
– A.E
3 hours ago












I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
– egreg
2 hours ago




I think it's better if the “with ...” line is just below the display. No blank line after end{align}. Also an exponential notation in line is not really good and exp is better, particularly with the fraction.
– egreg
2 hours ago












cheers. so to finalise, there's no need to change anything?
– A.E
2 hours ago




cheers. so to finalise, there's no need to change anything?
– A.E
2 hours ago












Just remove the blank line
– egreg
2 hours ago




Just remove the blank line
– egreg
2 hours ago










1 Answer
1






active

oldest

votes

















up vote
0
down vote













Is this what you wanted?



demo



documentclass{article}
usepackage{amsmath}
usepackage{amsfonts}
%usepackage{showframe}% dubugging tool

newcommand{iu}{text{i}}% just a guess. couldn't find definition

begin{document}
Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$.
Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
Now we have:
par% assuming parskip=0pt
begin{minipage}{dimexpr textwidth-parindent}
begin{flalign*}
chi{0} &= 1 &&\% only need it once
chi{1} &= a \
chi{2} &= a^2 \
chi{3} &= a^3 \
chi{4} &= a^4
end{flalign*}
hrule height0pt% a sort of horizontal strut
end{minipage}
with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.
end{document}





share|improve this answer























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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Is this what you wanted?



    demo



    documentclass{article}
    usepackage{amsmath}
    usepackage{amsfonts}
    %usepackage{showframe}% dubugging tool

    newcommand{iu}{text{i}}% just a guess. couldn't find definition

    begin{document}
    Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$.
    Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
    Now we have:
    par% assuming parskip=0pt
    begin{minipage}{dimexpr textwidth-parindent}
    begin{flalign*}
    chi{0} &= 1 &&\% only need it once
    chi{1} &= a \
    chi{2} &= a^2 \
    chi{3} &= a^3 \
    chi{4} &= a^4
    end{flalign*}
    hrule height0pt% a sort of horizontal strut
    end{minipage}
    with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.
    end{document}





    share|improve this answer



























      up vote
      0
      down vote













      Is this what you wanted?



      demo



      documentclass{article}
      usepackage{amsmath}
      usepackage{amsfonts}
      %usepackage{showframe}% dubugging tool

      newcommand{iu}{text{i}}% just a guess. couldn't find definition

      begin{document}
      Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$.
      Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
      Now we have:
      par% assuming parskip=0pt
      begin{minipage}{dimexpr textwidth-parindent}
      begin{flalign*}
      chi{0} &= 1 &&\% only need it once
      chi{1} &= a \
      chi{2} &= a^2 \
      chi{3} &= a^3 \
      chi{4} &= a^4
      end{flalign*}
      hrule height0pt% a sort of horizontal strut
      end{minipage}
      with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.
      end{document}





      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        Is this what you wanted?



        demo



        documentclass{article}
        usepackage{amsmath}
        usepackage{amsfonts}
        %usepackage{showframe}% dubugging tool

        newcommand{iu}{text{i}}% just a guess. couldn't find definition

        begin{document}
        Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$.
        Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
        Now we have:
        par% assuming parskip=0pt
        begin{minipage}{dimexpr textwidth-parindent}
        begin{flalign*}
        chi{0} &= 1 &&\% only need it once
        chi{1} &= a \
        chi{2} &= a^2 \
        chi{3} &= a^3 \
        chi{4} &= a^4
        end{flalign*}
        hrule height0pt% a sort of horizontal strut
        end{minipage}
        with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.
        end{document}





        share|improve this answer














        Is this what you wanted?



        demo



        documentclass{article}
        usepackage{amsmath}
        usepackage{amsfonts}
        %usepackage{showframe}% dubugging tool

        newcommand{iu}{text{i}}% just a guess. couldn't find definition

        begin{document}
        Let $G$ be a group, and let $G = mathbb{Z}_5 = {0,1,2,3,4}$.
        Let $chi:G rightarrow mathbb{Z} = {mathbb{Z}inmathbb{C}:lvert{mathbb{Z}rvert}=1}$.
        Now we have:
        par% assuming parskip=0pt
        begin{minipage}{dimexpr textwidth-parindent}
        begin{flalign*}
        chi{0} &= 1 &&\% only need it once
        chi{1} &= a \
        chi{2} &= a^2 \
        chi{3} &= a^3 \
        chi{4} &= a^4
        end{flalign*}
        hrule height0pt% a sort of horizontal strut
        end{minipage}
        with $a = exp{frac{2piiu}{5}}$ hence $a^5=1$.
        end{document}






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 1 hour ago

























        answered 1 hour ago









        John Kormylo

        42.9k12464




        42.9k12464






















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