Is there a well defined convolution where Fubini's theorem fails?












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$begingroup$


Suppose $f$ and $g$ are real functions such that $f*gin L^1$ Is there an example where Fubini's theorem might fail for the integral of the convolution? That is:



$$int_X(int_Yf(x-y)g(y)dy)dxnot=int_Y(int_Xf(x-y)g(y)dx)dy$$



I know that if $f,gin L^1$ then by Tonelli the product $f(x-y)g(y)$ is integrable in $Xtimes Y$ and hence Fubini's theorem holds, but is there an example where that's not the case?










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$endgroup$

















    1












    $begingroup$


    Suppose $f$ and $g$ are real functions such that $f*gin L^1$ Is there an example where Fubini's theorem might fail for the integral of the convolution? That is:



    $$int_X(int_Yf(x-y)g(y)dy)dxnot=int_Y(int_Xf(x-y)g(y)dx)dy$$



    I know that if $f,gin L^1$ then by Tonelli the product $f(x-y)g(y)$ is integrable in $Xtimes Y$ and hence Fubini's theorem holds, but is there an example where that's not the case?










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      Suppose $f$ and $g$ are real functions such that $f*gin L^1$ Is there an example where Fubini's theorem might fail for the integral of the convolution? That is:



      $$int_X(int_Yf(x-y)g(y)dy)dxnot=int_Y(int_Xf(x-y)g(y)dx)dy$$



      I know that if $f,gin L^1$ then by Tonelli the product $f(x-y)g(y)$ is integrable in $Xtimes Y$ and hence Fubini's theorem holds, but is there an example where that's not the case?










      share|cite|improve this question









      $endgroup$




      Suppose $f$ and $g$ are real functions such that $f*gin L^1$ Is there an example where Fubini's theorem might fail for the integral of the convolution? That is:



      $$int_X(int_Yf(x-y)g(y)dy)dxnot=int_Y(int_Xf(x-y)g(y)dx)dy$$



      I know that if $f,gin L^1$ then by Tonelli the product $f(x-y)g(y)$ is integrable in $Xtimes Y$ and hence Fubini's theorem holds, but is there an example where that's not the case?







      lebesgue-integral convolution iterated-integrals






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      share|cite|improve this question











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      share|cite|improve this question










      asked Dec 31 '18 at 21:46









      Bar AlonBar Alon

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