The property of coercivity in stochastic analysis












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$begingroup$


Given an SDE



$$ dX_{t}=b(t,X_{t})dt+sigma (t,X_{t}) dW_{t} $$



With $W$ the Wiener process. I have seen some results that under some assumptions on the coefficients $b,sigma$ such as :



i) Lipshitz



ii) Linear growth



iii) $sigma$ bounded



iv) $b$ coercive that is $b(t,X_{t})cdot X_{t} leq -alpha |X_{t}|^{2} $ where $alpha>0$



Then using krylov bogoliubov theorem we can find an invariant measure. My question is regarding the intuition behind the coercivity condition, I can see that the action of $dW_{t}$ is not really 'invariant' since it is a b.m and hence has Guassian distribution, therefore we need the drift term i.e the $dt$ to counteract the non-invarience of the b.m? What is it about coercivity that does this?










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    0












    $begingroup$


    Given an SDE



    $$ dX_{t}=b(t,X_{t})dt+sigma (t,X_{t}) dW_{t} $$



    With $W$ the Wiener process. I have seen some results that under some assumptions on the coefficients $b,sigma$ such as :



    i) Lipshitz



    ii) Linear growth



    iii) $sigma$ bounded



    iv) $b$ coercive that is $b(t,X_{t})cdot X_{t} leq -alpha |X_{t}|^{2} $ where $alpha>0$



    Then using krylov bogoliubov theorem we can find an invariant measure. My question is regarding the intuition behind the coercivity condition, I can see that the action of $dW_{t}$ is not really 'invariant' since it is a b.m and hence has Guassian distribution, therefore we need the drift term i.e the $dt$ to counteract the non-invarience of the b.m? What is it about coercivity that does this?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Given an SDE



      $$ dX_{t}=b(t,X_{t})dt+sigma (t,X_{t}) dW_{t} $$



      With $W$ the Wiener process. I have seen some results that under some assumptions on the coefficients $b,sigma$ such as :



      i) Lipshitz



      ii) Linear growth



      iii) $sigma$ bounded



      iv) $b$ coercive that is $b(t,X_{t})cdot X_{t} leq -alpha |X_{t}|^{2} $ where $alpha>0$



      Then using krylov bogoliubov theorem we can find an invariant measure. My question is regarding the intuition behind the coercivity condition, I can see that the action of $dW_{t}$ is not really 'invariant' since it is a b.m and hence has Guassian distribution, therefore we need the drift term i.e the $dt$ to counteract the non-invarience of the b.m? What is it about coercivity that does this?










      share|cite|improve this question











      $endgroup$




      Given an SDE



      $$ dX_{t}=b(t,X_{t})dt+sigma (t,X_{t}) dW_{t} $$



      With $W$ the Wiener process. I have seen some results that under some assumptions on the coefficients $b,sigma$ such as :



      i) Lipshitz



      ii) Linear growth



      iii) $sigma$ bounded



      iv) $b$ coercive that is $b(t,X_{t})cdot X_{t} leq -alpha |X_{t}|^{2} $ where $alpha>0$



      Then using krylov bogoliubov theorem we can find an invariant measure. My question is regarding the intuition behind the coercivity condition, I can see that the action of $dW_{t}$ is not really 'invariant' since it is a b.m and hence has Guassian distribution, therefore we need the drift term i.e the $dt$ to counteract the non-invarience of the b.m? What is it about coercivity that does this?







      stochastic-calculus stochastic-analysis sde stationary-processes coercive






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      edited Dec 11 '18 at 18:05







      Monty

















      asked Dec 9 '18 at 14:09









      MontyMonty

      36113




      36113






















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