SQL filtering query based on number of related rows












1















I have trouble wrapping my head around this problem.



After processing some queries I end up with a result of this kind:



SELECT col1, col2 FROM Whatever;

col1 col2
1 100
2 200
3 200
2 100


And I want to pull out 2 out of this, as 2 is the only value of col1 such that it corresponds to every existing value of col2 (100 and 200). If there was another row, say, 4 400 then I would want an empty result, as there would be no rows fulfilling this condition.



I was thinking ALL could help me, but then I realised that it's useless. I'd appreciate even athe slightest hint as to what to read.



Thanks in advance.



UPD: After some digging I came to conclusion that I need relational division, i.e.



Whatever <relational division> SELECT DISTINCT col2 FROM Whatever










share|improve this question

























  • Tag your question with the database you are using.

    – Gordon Linoff
    Nov 21 '18 at 16:23











  • @GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

    – Всеволод Тимченко
    Nov 21 '18 at 16:32











  • @YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

    – Всеволод Тимченко
    Nov 21 '18 at 16:33
















1















I have trouble wrapping my head around this problem.



After processing some queries I end up with a result of this kind:



SELECT col1, col2 FROM Whatever;

col1 col2
1 100
2 200
3 200
2 100


And I want to pull out 2 out of this, as 2 is the only value of col1 such that it corresponds to every existing value of col2 (100 and 200). If there was another row, say, 4 400 then I would want an empty result, as there would be no rows fulfilling this condition.



I was thinking ALL could help me, but then I realised that it's useless. I'd appreciate even athe slightest hint as to what to read.



Thanks in advance.



UPD: After some digging I came to conclusion that I need relational division, i.e.



Whatever <relational division> SELECT DISTINCT col2 FROM Whatever










share|improve this question

























  • Tag your question with the database you are using.

    – Gordon Linoff
    Nov 21 '18 at 16:23











  • @GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

    – Всеволод Тимченко
    Nov 21 '18 at 16:32











  • @YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

    – Всеволод Тимченко
    Nov 21 '18 at 16:33














1












1








1


1






I have trouble wrapping my head around this problem.



After processing some queries I end up with a result of this kind:



SELECT col1, col2 FROM Whatever;

col1 col2
1 100
2 200
3 200
2 100


And I want to pull out 2 out of this, as 2 is the only value of col1 such that it corresponds to every existing value of col2 (100 and 200). If there was another row, say, 4 400 then I would want an empty result, as there would be no rows fulfilling this condition.



I was thinking ALL could help me, but then I realised that it's useless. I'd appreciate even athe slightest hint as to what to read.



Thanks in advance.



UPD: After some digging I came to conclusion that I need relational division, i.e.



Whatever <relational division> SELECT DISTINCT col2 FROM Whatever










share|improve this question
















I have trouble wrapping my head around this problem.



After processing some queries I end up with a result of this kind:



SELECT col1, col2 FROM Whatever;

col1 col2
1 100
2 200
3 200
2 100


And I want to pull out 2 out of this, as 2 is the only value of col1 such that it corresponds to every existing value of col2 (100 and 200). If there was another row, say, 4 400 then I would want an empty result, as there would be no rows fulfilling this condition.



I was thinking ALL could help me, but then I realised that it's useless. I'd appreciate even athe slightest hint as to what to read.



Thanks in advance.



UPD: After some digging I came to conclusion that I need relational division, i.e.



Whatever <relational division> SELECT DISTINCT col2 FROM Whatever







sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 18:53







Всеволод Тимченко

















asked Nov 21 '18 at 16:21









Всеволод ТимченкоВсеволод Тимченко

10211




10211













  • Tag your question with the database you are using.

    – Gordon Linoff
    Nov 21 '18 at 16:23











  • @GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

    – Всеволод Тимченко
    Nov 21 '18 at 16:32











  • @YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

    – Всеволод Тимченко
    Nov 21 '18 at 16:33



















  • Tag your question with the database you are using.

    – Gordon Linoff
    Nov 21 '18 at 16:23











  • @GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

    – Всеволод Тимченко
    Nov 21 '18 at 16:32











  • @YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

    – Всеволод Тимченко
    Nov 21 '18 at 16:33

















Tag your question with the database you are using.

– Gordon Linoff
Nov 21 '18 at 16:23





Tag your question with the database you are using.

– Gordon Linoff
Nov 21 '18 at 16:23













@GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

– Всеволод Тимченко
Nov 21 '18 at 16:32





@GordonLinoff I'm interested specifically in vanilla SQL, not the implementations of it. I don't want use any implementation-specific stuff.

– Всеволод Тимченко
Nov 21 '18 at 16:32













@YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

– Всеволод Тимченко
Nov 21 '18 at 16:33





@YogeshSharma Why HAVING COUNT(*) > 1 though? There's nothing in my question that implies anything related to count larger than 1.

– Всеволод Тимченко
Nov 21 '18 at 16:33












1 Answer
1






active

oldest

votes


















1














One method uses window functions:



select col1, col2
from (select col1, col2,
count(distinct col2) over () as num_col2,
count(distinct col2) over (partition by col1) as num_col2_per_col1

from whatever
) t
where num_col2 = num_col2_per_col1;


Not all databases support count(distinct) as a window function. There are pretty simply work-arounds, if that is necessary, but count(distinct) as a window function is standard SQL.



If you only want "2" and not all the rows, then use select distinct col1.






share|improve this answer





















  • 1





    .great answer!!

    – stack0114106
    Jan 16 at 2:56











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














One method uses window functions:



select col1, col2
from (select col1, col2,
count(distinct col2) over () as num_col2,
count(distinct col2) over (partition by col1) as num_col2_per_col1

from whatever
) t
where num_col2 = num_col2_per_col1;


Not all databases support count(distinct) as a window function. There are pretty simply work-arounds, if that is necessary, but count(distinct) as a window function is standard SQL.



If you only want "2" and not all the rows, then use select distinct col1.






share|improve this answer





















  • 1





    .great answer!!

    – stack0114106
    Jan 16 at 2:56
















1














One method uses window functions:



select col1, col2
from (select col1, col2,
count(distinct col2) over () as num_col2,
count(distinct col2) over (partition by col1) as num_col2_per_col1

from whatever
) t
where num_col2 = num_col2_per_col1;


Not all databases support count(distinct) as a window function. There are pretty simply work-arounds, if that is necessary, but count(distinct) as a window function is standard SQL.



If you only want "2" and not all the rows, then use select distinct col1.






share|improve this answer





















  • 1





    .great answer!!

    – stack0114106
    Jan 16 at 2:56














1












1








1







One method uses window functions:



select col1, col2
from (select col1, col2,
count(distinct col2) over () as num_col2,
count(distinct col2) over (partition by col1) as num_col2_per_col1

from whatever
) t
where num_col2 = num_col2_per_col1;


Not all databases support count(distinct) as a window function. There are pretty simply work-arounds, if that is necessary, but count(distinct) as a window function is standard SQL.



If you only want "2" and not all the rows, then use select distinct col1.






share|improve this answer















One method uses window functions:



select col1, col2
from (select col1, col2,
count(distinct col2) over () as num_col2,
count(distinct col2) over (partition by col1) as num_col2_per_col1

from whatever
) t
where num_col2 = num_col2_per_col1;


Not all databases support count(distinct) as a window function. There are pretty simply work-arounds, if that is necessary, but count(distinct) as a window function is standard SQL.



If you only want "2" and not all the rows, then use select distinct col1.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 21 '18 at 16:31

























answered Nov 21 '18 at 16:25









Gordon LinoffGordon Linoff

789k35313418




789k35313418








  • 1





    .great answer!!

    – stack0114106
    Jan 16 at 2:56














  • 1





    .great answer!!

    – stack0114106
    Jan 16 at 2:56








1




1





.great answer!!

– stack0114106
Jan 16 at 2:56





.great answer!!

– stack0114106
Jan 16 at 2:56




















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