Finding multiple patterns in a string in Ruby












0















I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:



spamWords = Regexp.new("Delighted")

spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1


I iterated over an array of spamWord strings, but I was wondering if there is a simpler way of doing this.










share|improve this question

























  • If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

    – sawa
    Nov 21 '18 at 3:28
















0















I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:



spamWords = Regexp.new("Delighted")

spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1


I iterated over an array of spamWord strings, but I was wondering if there is a simpler way of doing this.










share|improve this question

























  • If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

    – sawa
    Nov 21 '18 at 3:28














0












0








0








I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:



spamWords = Regexp.new("Delighted")

spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1


I iterated over an array of spamWord strings, but I was wondering if there is a simpler way of doing this.










share|improve this question
















I am trying to find strings in an array that match multiple regular expression patterns. I figured out how to do this for one pattern as below:



spamWords = Regexp.new("Delighted")

spamCount1 = 0
spamArray.each do |word|
if word =~ spamWords
spamCount1 +=1
end
end
p spamCount1


I iterated over an array of spamWord strings, but I was wondering if there is a simpler way of doing this.







arrays ruby regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 3:23









sawa

131k29205303




131k29205303










asked Nov 20 '18 at 12:58









rhanlyrhanly

2616




2616













  • If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

    – sawa
    Nov 21 '18 at 3:28



















  • If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

    – sawa
    Nov 21 '18 at 3:28

















If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

– sawa
Nov 21 '18 at 3:28





If you just want to count rather than get the matches, then you should do: smapArray.count(&spamWords.method(:=~)).

– sawa
Nov 21 '18 at 3:28












1 Answer
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You can union multiple patterns into one regular expression, then perform the search exactly like you did below:



spamWords = Regexp.new("Delighted|Saddened")


You can also use Regexp.union to auto-generate this regexp for you:



spamWords = Regexp.union("Delighted", "Saddened")





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    1 Answer
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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    2














    You can union multiple patterns into one regular expression, then perform the search exactly like you did below:



    spamWords = Regexp.new("Delighted|Saddened")


    You can also use Regexp.union to auto-generate this regexp for you:



    spamWords = Regexp.union("Delighted", "Saddened")





    share|improve this answer




























      2














      You can union multiple patterns into one regular expression, then perform the search exactly like you did below:



      spamWords = Regexp.new("Delighted|Saddened")


      You can also use Regexp.union to auto-generate this regexp for you:



      spamWords = Regexp.union("Delighted", "Saddened")





      share|improve this answer


























        2












        2








        2







        You can union multiple patterns into one regular expression, then perform the search exactly like you did below:



        spamWords = Regexp.new("Delighted|Saddened")


        You can also use Regexp.union to auto-generate this regexp for you:



        spamWords = Regexp.union("Delighted", "Saddened")





        share|improve this answer













        You can union multiple patterns into one regular expression, then perform the search exactly like you did below:



        spamWords = Regexp.new("Delighted|Saddened")


        You can also use Regexp.union to auto-generate this regexp for you:



        spamWords = Regexp.union("Delighted", "Saddened")






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 '18 at 13:09









        Tom LordTom Lord

        15.3k22951




        15.3k22951
































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