Update a list of entity using Hibernate in Java
I get a list of entity from database using the code below:
List<NeginHotData> neginHotData = getNeginHotDataByStatus(null);
Then i need to change the Status field of them from NULL to "Active" and that's OK, the problem is that ,Is it possible to do this without iterating through the list of objects and updating them one by one? That doesn't sound efficient to me.
I need a solution to update them completely with each other because i have about 7000 record and iterating through the list of objects and updating them one by one isn't really a good solution .
java list hibernate sql-update
asked Nov 19 '18 at 15:36
SobhanSobhan
34
add a comment |
I get a list of entity from database using the code below:
List<NeginHotData> neginHotData = getNeginHotDataByStatus(null);
Then i need to change the Status field of them from NULL to "Active" and that's OK, the problem is that ,Is it possible to do this without iterating through the list of objects and updating them one by one? That doesn't sound efficient to me.
I need a solution to update them completely with each other because i have about 7000 record and iterating through the list of objects and updating them one by one isn't really a good solution .
java list hibernate sql-update
asked Nov 19 '18 at 15:36
SobhanSobhan
34
add a comment |
I get a list of entity from database using the code below:
List<NeginHotData> neginHotData = getNeginHotDataByStatus(null);
Then i need to change the Status field of them from NULL to "Active" and that's OK, the problem is that ,Is it possible to do this without iterating through the list of objects and updating them one by one? That doesn't sound efficient to me.
I need a solution to update them completely with each other because i have about 7000 record and iterating through the list of objects and updating them one by one isn't really a good solution .
java list hibernate sql-update
asked Nov 19 '18 at 15:36
SobhanSobhan
34
I get a list of entity from database using the code below:
List<NeginHotData> neginHotData = getNeginHotDataByStatus(null);
Then i need to change the Status field of them from NULL to "Active" and that's OK, the problem is that ,Is it possible to do this without iterating through the list of objects and updating them one by one? That doesn't sound efficient to me.
I need a solution to update them completely with each other because i have about 7000 record and iterating through the list of objects and updating them one by one isn't really a good solution .
java list hibernate sql-update
java list hibernate sql-update
asked Nov 19 '18 at 15:36
SobhanSobhan
34
asked Nov 19 '18 at 15:36
SobhanSobhan
34
asked Nov 19 '18 at 15:36
SobhanSobhan
34
asked Nov 19 '18 at 15:36
SobhanSobhan
34
asked Nov 19 '18 at 15:36
SobhanSobhan
34
34
add a comment |
add a comment |
1 Answer
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You can use HQL like this:
String hqlUpdate = "update NeginHotData c set c.status = :status where c.bla= :bla";
int updatedEntities = s.createQuery( hqlUpdate ).setString( "bla", bla).setString( "status", status).executeUpdate();
This works only if you set the same status for all entities involved.
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use HQL like this:
String hqlUpdate = "update NeginHotData c set c.status = :status where c.bla= :bla";
int updatedEntities = s.createQuery( hqlUpdate ).setString( "bla", bla).setString( "status", status).executeUpdate();
This works only if you set the same status for all entities involved.
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
add a comment |
You can use HQL like this:
String hqlUpdate = "update NeginHotData c set c.status = :status where c.bla= :bla";
int updatedEntities = s.createQuery( hqlUpdate ).setString( "bla", bla).setString( "status", status).executeUpdate();
This works only if you set the same status for all entities involved.
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
add a comment |
You can use HQL like this:
String hqlUpdate = "update NeginHotData c set c.status = :status where c.bla= :bla";
int updatedEntities = s.createQuery( hqlUpdate ).setString( "bla", bla).setString( "status", status).executeUpdate();
This works only if you set the same status for all entities involved.
You can use HQL like this:
String hqlUpdate = "update NeginHotData c set c.status = :status where c.bla= :bla";
int updatedEntities = s.createQuery( hqlUpdate ).setString( "bla", bla).setString( "status", status).executeUpdate();
This works only if you set the same status for all entities involved.
edited Nov 19 '18 at 16:00
answered Nov 19 '18 at 15:50
user10639668
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
add a comment |
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
it works,thank for your help!!
– Sobhan
Nov 21 '18 at 7:19
add a comment |
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