ggrepel: using position_dodge in combination with geom_label_repel
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
add a comment |
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
1
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 '18 at 22:35
add a comment |
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
I'm trying to label the outliers in a geom_boxplot using ggrepel::geom_label_repel. It works nicely when there's only one grouping variable, but when I try it for multiple grouping variables I run into a problem. The position argument in ggrepel doesn't seem to work very consistently for some reason, see this example:
library(tidyverse)
library(ggrepel)
set.seed(1337)
df <- tibble(x = rnorm(500),
g1 = factor(sample(c('A','B'), 500, replace = TRUE)),
g2 = factor(sample(c('A','B'), 500, replace = TRUE)),
rownames = 1:500)
is_outlier <- function(x) {
return(x < quantile(x, 0.25) - 1.5 * IQR(x) | x > quantile(x, 0.75) + 1.5 * IQR(x))
}
df_outliers <- df %>% group_by(g1, g2) %>% mutate(outlier=is_outlier(x))
ggplot(df_outliers, aes(x=g1, y=x, fill=g2)) +
geom_boxplot(width=0.3, position = position_dodge(0.5)) +
ggrepel::geom_label_repel(data=. %>% filter(outlier),
aes(label=rownames), position = position_dodge(0.8))
Is there a way to make the labels point to the accompanying dots using ggrepel?
r ggplot2 ggrepel
r ggplot2 ggrepel
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
edited Nov 19 '18 at 15:02
Rui Barradas
16.5k51730
16.5k51730
asked Nov 19 '18 at 14:58
RaviRavi
413
asked Nov 19 '18 at 14:58
RaviRavi
413
asked Nov 19 '18 at 14:58
RaviRavi
413
413
1
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 '18 at 22:35
add a comment |
1
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.
– aosmith
Nov 19 '18 at 22:35
1
1
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 '18 at 22:35
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 '18 at 22:35
add a comment |
1 Answer
1
active
oldest
votes
You can try this:
ggplot(df_outliers,
aes(x=g1, y=x, fill=g2, label=rownames)) +
geom_boxplot(width = 0.3, position = position_dodge(0.5)) +
geom_label_repel(data = . %>%
filter(outlier) %>%
group_by(g1) %>%
complete(g2, fill = list(x = 0, rownames = "")),
position = position_dodge(0.5),
box.padding = 1,
min.segment.length = 0,
show.legend = FALSE)
Explanations:
The data source for
geom_label_repel()follows aosmith's suggestion to add the B-A combination, filling0for x (any number would do, as long as it's not the default NA) and""for rowname (ggrepel won't plot empty labels, but will take them into account when dodging).box.paddingis set to 1 (increased from the default 0.25) to push the labels further away, so that the line segments are more visible.min.segment.lengthis set to 0 (decreased from the default 0.5) to force line segments to be plotted, no matter how short they are.
(show.legend = FALSE is optional. I just don't like seeing "a" letter show up in the legend.)
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
add a comment |
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You can try this:
ggplot(df_outliers,
aes(x=g1, y=x, fill=g2, label=rownames)) +
geom_boxplot(width = 0.3, position = position_dodge(0.5)) +
geom_label_repel(data = . %>%
filter(outlier) %>%
group_by(g1) %>%
complete(g2, fill = list(x = 0, rownames = "")),
position = position_dodge(0.5),
box.padding = 1,
min.segment.length = 0,
show.legend = FALSE)
Explanations:
The data source for
geom_label_repel()follows aosmith's suggestion to add the B-A combination, filling0for x (any number would do, as long as it's not the default NA) and""for rowname (ggrepel won't plot empty labels, but will take them into account when dodging).box.paddingis set to 1 (increased from the default 0.25) to push the labels further away, so that the line segments are more visible.min.segment.lengthis set to 0 (decreased from the default 0.5) to force line segments to be plotted, no matter how short they are.
(show.legend = FALSE is optional. I just don't like seeing "a" letter show up in the legend.)
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
add a comment |
You can try this:
ggplot(df_outliers,
aes(x=g1, y=x, fill=g2, label=rownames)) +
geom_boxplot(width = 0.3, position = position_dodge(0.5)) +
geom_label_repel(data = . %>%
filter(outlier) %>%
group_by(g1) %>%
complete(g2, fill = list(x = 0, rownames = "")),
position = position_dodge(0.5),
box.padding = 1,
min.segment.length = 0,
show.legend = FALSE)
Explanations:
The data source for
geom_label_repel()follows aosmith's suggestion to add the B-A combination, filling0for x (any number would do, as long as it's not the default NA) and""for rowname (ggrepel won't plot empty labels, but will take them into account when dodging).box.paddingis set to 1 (increased from the default 0.25) to push the labels further away, so that the line segments are more visible.min.segment.lengthis set to 0 (decreased from the default 0.5) to force line segments to be plotted, no matter how short they are.
(show.legend = FALSE is optional. I just don't like seeing "a" letter show up in the legend.)
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
add a comment |
You can try this:
ggplot(df_outliers,
aes(x=g1, y=x, fill=g2, label=rownames)) +
geom_boxplot(width = 0.3, position = position_dodge(0.5)) +
geom_label_repel(data = . %>%
filter(outlier) %>%
group_by(g1) %>%
complete(g2, fill = list(x = 0, rownames = "")),
position = position_dodge(0.5),
box.padding = 1,
min.segment.length = 0,
show.legend = FALSE)
Explanations:
The data source for
geom_label_repel()follows aosmith's suggestion to add the B-A combination, filling0for x (any number would do, as long as it's not the default NA) and""for rowname (ggrepel won't plot empty labels, but will take them into account when dodging).box.paddingis set to 1 (increased from the default 0.25) to push the labels further away, so that the line segments are more visible.min.segment.lengthis set to 0 (decreased from the default 0.5) to force line segments to be plotted, no matter how short they are.
(show.legend = FALSE is optional. I just don't like seeing "a" letter show up in the legend.)
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
You can try this:
ggplot(df_outliers,
aes(x=g1, y=x, fill=g2, label=rownames)) +
geom_boxplot(width = 0.3, position = position_dodge(0.5)) +
geom_label_repel(data = . %>%
filter(outlier) %>%
group_by(g1) %>%
complete(g2, fill = list(x = 0, rownames = "")),
position = position_dodge(0.5),
box.padding = 1,
min.segment.length = 0,
show.legend = FALSE)
Explanations:
The data source for
geom_label_repel()follows aosmith's suggestion to add the B-A combination, filling0for x (any number would do, as long as it's not the default NA) and""for rowname (ggrepel won't plot empty labels, but will take them into account when dodging).box.paddingis set to 1 (increased from the default 0.25) to push the labels further away, so that the line segments are more visible.min.segment.lengthis set to 0 (decreased from the default 0.5) to force line segments to be plotted, no matter how short they are.
(show.legend = FALSE is optional. I just don't like seeing "a" letter show up in the legend.)
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
answered Jan 16 at 6:30
Z.LinZ.Lin
10.9k21729
10.9k21729
add a comment |
add a comment |
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1
I think at least part of the problem has to do with having no B (g1) A (g2) outliers. You can get the dodging by adding that combination in,
. %>% filter(outlier) %>% group_by(g1) %>% complete(g2). However, this doesn't fix the problem of how the lines are drawn with ggrepel.– aosmith
Nov 19 '18 at 22:35