Tikz regular polygon corner names












4















The following code gives No shape named S.corner 1 is known. error. What am I doing wrong?



documentclass[tikz,border=10pt]{standalone}
usetikzlibrary{angles}
usetikzlibrary{shapes}
usetikzlibrary{shapes.geometric}
begin{document}
begin{tikzpicture}
node[name=S,regular polygon, regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
pic [draw, angle radius=.6cm] {angle = S.corner 1--S.corner 6--S.corner 5};
end{tikzpicture}
end{document}









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  • I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

    – Anthony Labarre
    Mar 15 at 16:16






  • 1





    That's the standard problem that the angle construction adds point anchors center to the coordinates.

    – marmot
    Mar 15 at 16:38
















4















The following code gives No shape named S.corner 1 is known. error. What am I doing wrong?



documentclass[tikz,border=10pt]{standalone}
usetikzlibrary{angles}
usetikzlibrary{shapes}
usetikzlibrary{shapes.geometric}
begin{document}
begin{tikzpicture}
node[name=S,regular polygon, regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
pic [draw, angle radius=.6cm] {angle = S.corner 1--S.corner 6--S.corner 5};
end{tikzpicture}
end{document}









share|improve this question

























  • I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

    – Anthony Labarre
    Mar 15 at 16:16






  • 1





    That's the standard problem that the angle construction adds point anchors center to the coordinates.

    – marmot
    Mar 15 at 16:38














4












4








4








The following code gives No shape named S.corner 1 is known. error. What am I doing wrong?



documentclass[tikz,border=10pt]{standalone}
usetikzlibrary{angles}
usetikzlibrary{shapes}
usetikzlibrary{shapes.geometric}
begin{document}
begin{tikzpicture}
node[name=S,regular polygon, regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
pic [draw, angle radius=.6cm] {angle = S.corner 1--S.corner 6--S.corner 5};
end{tikzpicture}
end{document}









share|improve this question
















The following code gives No shape named S.corner 1 is known. error. What am I doing wrong?



documentclass[tikz,border=10pt]{standalone}
usetikzlibrary{angles}
usetikzlibrary{shapes}
usetikzlibrary{shapes.geometric}
begin{document}
begin{tikzpicture}
node[name=S,regular polygon, regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
pic [draw, angle radius=.6cm] {angle = S.corner 1--S.corner 6--S.corner 5};
end{tikzpicture}
end{document}






tikz-pgf






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edited Mar 15 at 15:46







blackened

















asked Mar 15 at 15:39









blackenedblackened

1,670714




1,670714













  • I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

    – Anthony Labarre
    Mar 15 at 16:16






  • 1





    That's the standard problem that the angle construction adds point anchors center to the coordinates.

    – marmot
    Mar 15 at 16:38



















  • I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

    – Anthony Labarre
    Mar 15 at 16:16






  • 1





    That's the standard problem that the angle construction adds point anchors center to the coordinates.

    – marmot
    Mar 15 at 16:38

















I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

– Anthony Labarre
Mar 15 at 16:16





I don't know the pic command, but draw (S.corner 1) -- (S.corner 6); works fine with your example.

– Anthony Labarre
Mar 15 at 16:16




1




1





That's the standard problem that the angle construction adds point anchors center to the coordinates.

– marmot
Mar 15 at 16:38





That's the standard problem that the angle construction adds point anchors center to the coordinates.

– marmot
Mar 15 at 16:38










1 Answer
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oldest

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tikzlibraryangles.code.tex contains



deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
path [name prefix ..] [pic actions, draw=none] (#2.center)
-- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
-- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
-- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
-- cycle;
}%


from which you see that it attaches .center to the second coordinate #2. This does not work if #2 is already an anchor. To work around this problem (rather than redefining tikz@lib@rightangle@background and the other commands that attach .center), you may just define auxiliary coordinates.



documentclass[tikz,border=10pt]{standalone}
usetikzlibrary{angles}
usetikzlibrary{shapes}
usetikzlibrary{shapes.geometric}
begin{document}
begin{tikzpicture}
node[name=S,regular polygon,
regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
path foreach X in {1,...,9} {(S.corner X) coordinate (corner X)};
pic [draw, angle radius=.6cm] {angle = corner 1--corner 6--corner 5};
end{tikzpicture}
end{document}


enter image description here






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    2














    tikzlibraryangles.code.tex contains



    deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
    path [name prefix ..] [pic actions, draw=none] (#2.center)
    -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
    -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
    -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
    -- cycle;
    }%


    from which you see that it attaches .center to the second coordinate #2. This does not work if #2 is already an anchor. To work around this problem (rather than redefining tikz@lib@rightangle@background and the other commands that attach .center), you may just define auxiliary coordinates.



    documentclass[tikz,border=10pt]{standalone}
    usetikzlibrary{angles}
    usetikzlibrary{shapes}
    usetikzlibrary{shapes.geometric}
    begin{document}
    begin{tikzpicture}
    node[name=S,regular polygon,
    regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
    path foreach X in {1,...,9} {(S.corner X) coordinate (corner X)};
    pic [draw, angle radius=.6cm] {angle = corner 1--corner 6--corner 5};
    end{tikzpicture}
    end{document}


    enter image description here






    share|improve this answer




























      2














      tikzlibraryangles.code.tex contains



      deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
      path [name prefix ..] [pic actions, draw=none] (#2.center)
      -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
      -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
      -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
      -- cycle;
      }%


      from which you see that it attaches .center to the second coordinate #2. This does not work if #2 is already an anchor. To work around this problem (rather than redefining tikz@lib@rightangle@background and the other commands that attach .center), you may just define auxiliary coordinates.



      documentclass[tikz,border=10pt]{standalone}
      usetikzlibrary{angles}
      usetikzlibrary{shapes}
      usetikzlibrary{shapes.geometric}
      begin{document}
      begin{tikzpicture}
      node[name=S,regular polygon,
      regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
      path foreach X in {1,...,9} {(S.corner X) coordinate (corner X)};
      pic [draw, angle radius=.6cm] {angle = corner 1--corner 6--corner 5};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer


























        2












        2








        2







        tikzlibraryangles.code.tex contains



        deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
        path [name prefix ..] [pic actions, draw=none] (#2.center)
        -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
        -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
        -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
        -- cycle;
        }%


        from which you see that it attaches .center to the second coordinate #2. This does not work if #2 is already an anchor. To work around this problem (rather than redefining tikz@lib@rightangle@background and the other commands that attach .center), you may just define auxiliary coordinates.



        documentclass[tikz,border=10pt]{standalone}
        usetikzlibrary{angles}
        usetikzlibrary{shapes}
        usetikzlibrary{shapes.geometric}
        begin{document}
        begin{tikzpicture}
        node[name=S,regular polygon,
        regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
        path foreach X in {1,...,9} {(S.corner X) coordinate (corner X)};
        pic [draw, angle radius=.6cm] {angle = corner 1--corner 6--corner 5};
        end{tikzpicture}
        end{document}


        enter image description here






        share|improve this answer













        tikzlibraryangles.code.tex contains



        deftikz@lib@rightangle@background#1--#2--#3pgf@stop{%
        path [name prefix ..] [pic actions, draw=none] (#2.center)
        -- ++(tikz@start@angle@temp:tikz@lib@angle@rad pt)
        -- ++(tikz@end@angle@temp:tikz@lib@angle@rad pt)
        -- ++(tikz@start@angle@temp:-tikz@lib@angle@rad pt)
        -- cycle;
        }%


        from which you see that it attaches .center to the second coordinate #2. This does not work if #2 is already an anchor. To work around this problem (rather than redefining tikz@lib@rightangle@background and the other commands that attach .center), you may just define auxiliary coordinates.



        documentclass[tikz,border=10pt]{standalone}
        usetikzlibrary{angles}
        usetikzlibrary{shapes}
        usetikzlibrary{shapes.geometric}
        begin{document}
        begin{tikzpicture}
        node[name=S,regular polygon,
        regular polygon sides=9, draw, minimum width=6cm] at (0,0) {};
        path foreach X in {1,...,9} {(S.corner X) coordinate (corner X)};
        pic [draw, angle radius=.6cm] {angle = corner 1--corner 6--corner 5};
        end{tikzpicture}
        end{document}


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 15 at 16:45









        marmotmarmot

        111k5140264




        111k5140264






























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