How to convert a DateTime variable in awk to seconds?












1















I have a variable in which stores the DateTime in awk



test=$(f["DateTime"])

print "Printing Test variable:",test


Output:



 Printing Test variable:,"2018-12-18 18:36:55"


I want to convert the value in test to seconds



Could anybody tell me how to do that in awk



Using mktime() is giving -1 as output



    print mktime(gensub(/[ :-]/," ","g",test))


My Input data (CSV File)is like below



DateTime,Dealer,Some Value,State,CallEndTime,Some Value,TotalDuration,,..



 "2019-01-07 11:35:42","Car","fab","foo",,"bar","100","boo",..


I got the DateTime value from this,






command-line awk







share|improve this question





























    1















    I have a variable in which stores the DateTime in awk



    test=$(f["DateTime"])
    
print "Printing Test variable:",test


    Output:



     Printing Test variable:,"2018-12-18 18:36:55"


    I want to convert the value in test to seconds



    Could anybody tell me how to do that in awk



    Using mktime() is giving -1 as output



        print mktime(gensub(/[ :-]/," ","g",test))


    My Input data (CSV File)is like below



    DateTime,Dealer,Some Value,State,CallEndTime,Some Value,TotalDuration,,..
    

    
 "2019-01-07 11:35:42","Car","fab","foo",,"bar","100","boo",..


    I got the DateTime value from this,






    command-line awk







    share|improve this question



























      1












      1








      1








      I have a variable in which stores the DateTime in awk



      test=$(f["DateTime"])
      
print "Printing Test variable:",test


      Output:



       Printing Test variable:,"2018-12-18 18:36:55"


      I want to convert the value in test to seconds



      Could anybody tell me how to do that in awk



      Using mktime() is giving -1 as output



          print mktime(gensub(/[ :-]/," ","g",test))


      My Input data (CSV File)is like below



      DateTime,Dealer,Some Value,State,CallEndTime,Some Value,TotalDuration,,..
      

      
 "2019-01-07 11:35:42","Car","fab","foo",,"bar","100","boo",..


      I got the DateTime value from this,






      command-line awk







      share|improve this question
















      I have a variable in which stores the DateTime in awk



      test=$(f["DateTime"])
      
print "Printing Test variable:",test


      Output:



       Printing Test variable:,"2018-12-18 18:36:55"


      I want to convert the value in test to seconds



      Could anybody tell me how to do that in awk



      Using mktime() is giving -1 as output



          print mktime(gensub(/[ :-]/," ","g",test))


      My Input data (CSV File)is like below



      DateTime,Dealer,Some Value,State,CallEndTime,Some Value,TotalDuration,,..
      

      
 "2019-01-07 11:35:42","Car","fab","foo",,"bar","100","boo",..


      I got the DateTime value from this,






      command-line awk




      command-line awk






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 23 at 4:04







      mittu

















      asked Jan 23 at 3:23









      mittumittu

      83




      83






















          1 Answer
          1






          active

          oldest

          votes


















          1














          If you have GNU awk (gawk) you can use its mktime function - however the input must be a space-separated datespec of the form "YYYY MM DD HH MM SS [DST]". The date fields in your variable are in the right order, but you will need to replace the delimiters with spaces:



          $ gawk -v test="2018-12-18 18:36:55" 'BEGIN{print mktime(gensub(/[ :-]/," ","g",test))}'
          
1545176215


          See for example Time Functions in the GNU Awk User's Guide




          If your string is enclosed in double quotes, you will need to remove those as well:



          $ gawk -v test='"2018-12-18 18:36:55"' 'BEGIN{print mktime(gensub(/[ ":-]/," ","g",test))}'
          
1545176215





          share|improve this answer


























          • I tried this,but its giving me -1 as O/P, Please check the edited question

            – mittu
            Jan 23 at 4:05











          • @mittu please see update

            – steeldriver
            Jan 23 at 4:09











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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          If you have GNU awk (gawk) you can use its mktime function - however the input must be a space-separated datespec of the form "YYYY MM DD HH MM SS [DST]". The date fields in your variable are in the right order, but you will need to replace the delimiters with spaces:



          $ gawk -v test="2018-12-18 18:36:55" 'BEGIN{print mktime(gensub(/[ :-]/," ","g",test))}'
          
1545176215


          See for example Time Functions in the GNU Awk User's Guide




          If your string is enclosed in double quotes, you will need to remove those as well:



          $ gawk -v test='"2018-12-18 18:36:55"' 'BEGIN{print mktime(gensub(/[ ":-]/," ","g",test))}'
          
1545176215





          share|improve this answer


























          • I tried this,but its giving me -1 as O/P, Please check the edited question

            – mittu
            Jan 23 at 4:05











          • @mittu please see update

            – steeldriver
            Jan 23 at 4:09
















          1














          If you have GNU awk (gawk) you can use its mktime function - however the input must be a space-separated datespec of the form "YYYY MM DD HH MM SS [DST]". The date fields in your variable are in the right order, but you will need to replace the delimiters with spaces:



          $ gawk -v test="2018-12-18 18:36:55" 'BEGIN{print mktime(gensub(/[ :-]/," ","g",test))}'
          
1545176215


          See for example Time Functions in the GNU Awk User's Guide




          If your string is enclosed in double quotes, you will need to remove those as well:



          $ gawk -v test='"2018-12-18 18:36:55"' 'BEGIN{print mktime(gensub(/[ ":-]/," ","g",test))}'
          
1545176215





          share|improve this answer


























          • I tried this,but its giving me -1 as O/P, Please check the edited question

            – mittu
            Jan 23 at 4:05











          • @mittu please see update

            – steeldriver
            Jan 23 at 4:09














          1












          1








          1







          If you have GNU awk (gawk) you can use its mktime function - however the input must be a space-separated datespec of the form "YYYY MM DD HH MM SS [DST]". The date fields in your variable are in the right order, but you will need to replace the delimiters with spaces:



          $ gawk -v test="2018-12-18 18:36:55" 'BEGIN{print mktime(gensub(/[ :-]/," ","g",test))}'
          
1545176215


          See for example Time Functions in the GNU Awk User's Guide




          If your string is enclosed in double quotes, you will need to remove those as well:



          $ gawk -v test='"2018-12-18 18:36:55"' 'BEGIN{print mktime(gensub(/[ ":-]/," ","g",test))}'
          
1545176215





          share|improve this answer















          If you have GNU awk (gawk) you can use its mktime function - however the input must be a space-separated datespec of the form "YYYY MM DD HH MM SS [DST]". The date fields in your variable are in the right order, but you will need to replace the delimiters with spaces:



          $ gawk -v test="2018-12-18 18:36:55" 'BEGIN{print mktime(gensub(/[ :-]/," ","g",test))}'
          
1545176215


          See for example Time Functions in the GNU Awk User's Guide




          If your string is enclosed in double quotes, you will need to remove those as well:



          $ gawk -v test='"2018-12-18 18:36:55"' 'BEGIN{print mktime(gensub(/[ ":-]/," ","g",test))}'
          
1545176215






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 23 at 4:09

























          answered Jan 23 at 3:45









          steeldriversteeldriver

          68.8k11113184




          68.8k11113184













          • I tried this,but its giving me -1 as O/P, Please check the edited question

            – mittu
            Jan 23 at 4:05











          • @mittu please see update

            – steeldriver
            Jan 23 at 4:09



















          • I tried this,but its giving me -1 as O/P, Please check the edited question

            – mittu
            Jan 23 at 4:05











          • @mittu please see update

            – steeldriver
            Jan 23 at 4:09

















          I tried this,but its giving me -1 as O/P, Please check the edited question

          – mittu
          Jan 23 at 4:05





          I tried this,but its giving me -1 as O/P, Please check the edited question

          – mittu
          Jan 23 at 4:05













          @mittu please see update

          – steeldriver
          Jan 23 at 4:09





          @mittu please see update

          – steeldriver
          Jan 23 at 4:09


















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