How to control the location of my circle?












1















So, I'm using CodeAvengers to learn how to make games. It recently taught me how to use onMouseDown and a few other things like that. It showed me what attributes to use to make something appear or happen when I click down, drag the mouse, or other things like that. I managed to re-create that in a way that would work on Notepad ++, but there's a certain part that I don't really know how to do. How do I make the circle appear where I click the mouse, instead of just popping up in the corner?



Here's my code



<!DOCTYPE html>
<html>
<body>
<canvas id = "gameCanvas" width="500" height="500" style="border:4px solid
black"></canvas>
<script type = "text/javascript">
var myCanvas = document.getElementById("gameCanvas");
var ctx = myCanvas.getContext("2d");

window.onmousedown = function(event){
ctx.beginPath();
ctx.arc(100,75,50,0,2*Math.PI);
ctx.stroke();
}
</script>
</body>
</html>









share|improve this question





























    1















    So, I'm using CodeAvengers to learn how to make games. It recently taught me how to use onMouseDown and a few other things like that. It showed me what attributes to use to make something appear or happen when I click down, drag the mouse, or other things like that. I managed to re-create that in a way that would work on Notepad ++, but there's a certain part that I don't really know how to do. How do I make the circle appear where I click the mouse, instead of just popping up in the corner?



    Here's my code



    <!DOCTYPE html>
    <html>
    <body>
    <canvas id = "gameCanvas" width="500" height="500" style="border:4px solid
    black"></canvas>
    <script type = "text/javascript">
    var myCanvas = document.getElementById("gameCanvas");
    var ctx = myCanvas.getContext("2d");

    window.onmousedown = function(event){
    ctx.beginPath();
    ctx.arc(100,75,50,0,2*Math.PI);
    ctx.stroke();
    }
    </script>
    </body>
    </html>









    share|improve this question



























      1












      1








      1








      So, I'm using CodeAvengers to learn how to make games. It recently taught me how to use onMouseDown and a few other things like that. It showed me what attributes to use to make something appear or happen when I click down, drag the mouse, or other things like that. I managed to re-create that in a way that would work on Notepad ++, but there's a certain part that I don't really know how to do. How do I make the circle appear where I click the mouse, instead of just popping up in the corner?



      Here's my code



      <!DOCTYPE html>
      <html>
      <body>
      <canvas id = "gameCanvas" width="500" height="500" style="border:4px solid
      black"></canvas>
      <script type = "text/javascript">
      var myCanvas = document.getElementById("gameCanvas");
      var ctx = myCanvas.getContext("2d");

      window.onmousedown = function(event){
      ctx.beginPath();
      ctx.arc(100,75,50,0,2*Math.PI);
      ctx.stroke();
      }
      </script>
      </body>
      </html>









      share|improve this question
















      So, I'm using CodeAvengers to learn how to make games. It recently taught me how to use onMouseDown and a few other things like that. It showed me what attributes to use to make something appear or happen when I click down, drag the mouse, or other things like that. I managed to re-create that in a way that would work on Notepad ++, but there's a certain part that I don't really know how to do. How do I make the circle appear where I click the mouse, instead of just popping up in the corner?



      Here's my code



      <!DOCTYPE html>
      <html>
      <body>
      <canvas id = "gameCanvas" width="500" height="500" style="border:4px solid
      black"></canvas>
      <script type = "text/javascript">
      var myCanvas = document.getElementById("gameCanvas");
      var ctx = myCanvas.getContext("2d");

      window.onmousedown = function(event){
      ctx.beginPath();
      ctx.arc(100,75,50,0,2*Math.PI);
      ctx.stroke();
      }
      </script>
      </body>
      </html>






      javascript html5-canvas drawing






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      edited Nov 22 '18 at 5:13









      JP4

      148514




      148514










      asked Nov 22 '18 at 0:41









      Khadijah MuhammadKhadijah Muhammad

      174




      174
























          1 Answer
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          Need to grab the event's mouse clientX and clientY coordinates and set the circle's (x,y) coordinate to them.



          ctx.arc(event.clientX, event.clientY, 50, 0, 2*Math.PI);





          share|improve this answer


























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            Need to grab the event's mouse clientX and clientY coordinates and set the circle's (x,y) coordinate to them.



            ctx.arc(event.clientX, event.clientY, 50, 0, 2*Math.PI);





            share|improve this answer






























              2














              Need to grab the event's mouse clientX and clientY coordinates and set the circle's (x,y) coordinate to them.



              ctx.arc(event.clientX, event.clientY, 50, 0, 2*Math.PI);





              share|improve this answer




























                2












                2








                2







                Need to grab the event's mouse clientX and clientY coordinates and set the circle's (x,y) coordinate to them.



                ctx.arc(event.clientX, event.clientY, 50, 0, 2*Math.PI);





                share|improve this answer















                Need to grab the event's mouse clientX and clientY coordinates and set the circle's (x,y) coordinate to them.



                ctx.arc(event.clientX, event.clientY, 50, 0, 2*Math.PI);






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 22 '18 at 1:07

























                answered Nov 22 '18 at 1:01









                Drew ReeseDrew Reese

                970211




                970211
































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