How to specify a condition when equating expressions











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I do not know how this concept is called in mathematics, but when you are working on an expression, you may operate step by step, saying: "this equals this, and equals this, and equals this..."



But sometimes, you need to specify "this equals this, only if x is not zero", for example when operating and putting x into a denominator.



When drawing on a paper you just write around the equal symbol a note and say: "from now on, x cannot be zero", but I don't know how to express this on a TeX version of a mathematical process representation.



I tried it like this, but it doesn't seem very accurate to me:



Example



What is your suggestion or the standard way of achieving this, if any? Thank you.



Edit:



This is the LaTeX code of the attached image example.



begin{aligned}Lleft[ fleft( tright) right] =int ^{infty }_{0}e^{-st}cdot fleft( tright) dt=lim _{brightarrow infty }int ^{b}_{0}e^{-st}.fleft( tright) dt=lim _{brightarrow infty }left[ int ^{3}_{0}e^{-st}cdot 0cdot dt+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =\
=lim _{brightarrow infty }left[ 0+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =lim _{brightarrow infty }left[ dfrac {e^{-st}}{-s}right] ^{b}_{3}=left[ forall sneq 0right] =end{aligned}









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    BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
    – Teepeemm
    Dec 6 at 1:45

















up vote
1
down vote

favorite












I do not know how this concept is called in mathematics, but when you are working on an expression, you may operate step by step, saying: "this equals this, and equals this, and equals this..."



But sometimes, you need to specify "this equals this, only if x is not zero", for example when operating and putting x into a denominator.



When drawing on a paper you just write around the equal symbol a note and say: "from now on, x cannot be zero", but I don't know how to express this on a TeX version of a mathematical process representation.



I tried it like this, but it doesn't seem very accurate to me:



Example



What is your suggestion or the standard way of achieving this, if any? Thank you.



Edit:



This is the LaTeX code of the attached image example.



begin{aligned}Lleft[ fleft( tright) right] =int ^{infty }_{0}e^{-st}cdot fleft( tright) dt=lim _{brightarrow infty }int ^{b}_{0}e^{-st}.fleft( tright) dt=lim _{brightarrow infty }left[ int ^{3}_{0}e^{-st}cdot 0cdot dt+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =\
=lim _{brightarrow infty }left[ 0+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =lim _{brightarrow infty }left[ dfrac {e^{-st}}{-s}right] ^{b}_{3}=left[ forall sneq 0right] =end{aligned}









share|improve this question




















  • 1




    BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
    – Teepeemm
    Dec 6 at 1:45















up vote
1
down vote

favorite









up vote
1
down vote

favorite











I do not know how this concept is called in mathematics, but when you are working on an expression, you may operate step by step, saying: "this equals this, and equals this, and equals this..."



But sometimes, you need to specify "this equals this, only if x is not zero", for example when operating and putting x into a denominator.



When drawing on a paper you just write around the equal symbol a note and say: "from now on, x cannot be zero", but I don't know how to express this on a TeX version of a mathematical process representation.



I tried it like this, but it doesn't seem very accurate to me:



Example



What is your suggestion or the standard way of achieving this, if any? Thank you.



Edit:



This is the LaTeX code of the attached image example.



begin{aligned}Lleft[ fleft( tright) right] =int ^{infty }_{0}e^{-st}cdot fleft( tright) dt=lim _{brightarrow infty }int ^{b}_{0}e^{-st}.fleft( tright) dt=lim _{brightarrow infty }left[ int ^{3}_{0}e^{-st}cdot 0cdot dt+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =\
=lim _{brightarrow infty }left[ 0+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =lim _{brightarrow infty }left[ dfrac {e^{-st}}{-s}right] ^{b}_{3}=left[ forall sneq 0right] =end{aligned}









share|improve this question















I do not know how this concept is called in mathematics, but when you are working on an expression, you may operate step by step, saying: "this equals this, and equals this, and equals this..."



But sometimes, you need to specify "this equals this, only if x is not zero", for example when operating and putting x into a denominator.



When drawing on a paper you just write around the equal symbol a note and say: "from now on, x cannot be zero", but I don't know how to express this on a TeX version of a mathematical process representation.



I tried it like this, but it doesn't seem very accurate to me:



Example



What is your suggestion or the standard way of achieving this, if any? Thank you.



Edit:



This is the LaTeX code of the attached image example.



begin{aligned}Lleft[ fleft( tright) right] =int ^{infty }_{0}e^{-st}cdot fleft( tright) dt=lim _{brightarrow infty }int ^{b}_{0}e^{-st}.fleft( tright) dt=lim _{brightarrow infty }left[ int ^{3}_{0}e^{-st}cdot 0cdot dt+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =\
=lim _{brightarrow infty }left[ 0+int ^{b}_{3}e^{-st}cdot 1cdot dtright] =lim _{brightarrow infty }left[ dfrac {e^{-st}}{-s}right] ^{b}_{3}=left[ forall sneq 0right] =end{aligned}






equations






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edited Dec 5 at 18:16

























asked Dec 5 at 16:51









Alvaro Franz

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  • 1




    BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
    – Teepeemm
    Dec 6 at 1:45
















  • 1




    BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
    – Teepeemm
    Dec 6 at 1:45










1




1




BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
– Teepeemm
Dec 6 at 1:45






BTW, I'm pretty sure we need s > 0, otherwise the integral doesn't converge.
– Teepeemm
Dec 6 at 1:45












1 Answer
1






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oldest

votes

















up vote
3
down vote



accepted










Conditionals in mathematics are often expressed using a { <expr> | <cond> } format, read as <expr> given <cond>. Perhaps consider that here:



enter image description here



documentclass{article}

usepackage{mathtools}
newcommand{Laplace}{mathcal{L}laplace}
DeclarePairedDelimiter{laplace}{[}{]}
newcommand{dt}{,mathrm{d}t}

begin{document}

begin{align*}
Laplace[big]{f(t)}
&= int_0^infty e^{-st} cdot f(t) dt \
&= lim_{b rightarrow infty} int_0^b e^{-st} cdot f(t) dt \
&= lim_{b rightarrow infty} biggl[ int_0^3 e^{-st} cdot 0 dt + int_3^b e^{-st} cdot 1 dt biggr] \
&= lim_{b rightarrow infty} biggl[ 0 + int_3^b e^{-st} cdot 1 dt biggr] \
&= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggmvert s neq 0 biggr]_3^b
end{align*}

end{document}


or just include it as a description:



enter image description here



begin{align*}
% ...
&= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggr]_3^b qquad text{(where $s neq 0$)}
end{align*}





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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Conditionals in mathematics are often expressed using a { <expr> | <cond> } format, read as <expr> given <cond>. Perhaps consider that here:



    enter image description here



    documentclass{article}

    usepackage{mathtools}
    newcommand{Laplace}{mathcal{L}laplace}
    DeclarePairedDelimiter{laplace}{[}{]}
    newcommand{dt}{,mathrm{d}t}

    begin{document}

    begin{align*}
    Laplace[big]{f(t)}
    &= int_0^infty e^{-st} cdot f(t) dt \
    &= lim_{b rightarrow infty} int_0^b e^{-st} cdot f(t) dt \
    &= lim_{b rightarrow infty} biggl[ int_0^3 e^{-st} cdot 0 dt + int_3^b e^{-st} cdot 1 dt biggr] \
    &= lim_{b rightarrow infty} biggl[ 0 + int_3^b e^{-st} cdot 1 dt biggr] \
    &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggmvert s neq 0 biggr]_3^b
    end{align*}

    end{document}


    or just include it as a description:



    enter image description here



    begin{align*}
    % ...
    &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggr]_3^b qquad text{(where $s neq 0$)}
    end{align*}





    share|improve this answer

























      up vote
      3
      down vote



      accepted










      Conditionals in mathematics are often expressed using a { <expr> | <cond> } format, read as <expr> given <cond>. Perhaps consider that here:



      enter image description here



      documentclass{article}

      usepackage{mathtools}
      newcommand{Laplace}{mathcal{L}laplace}
      DeclarePairedDelimiter{laplace}{[}{]}
      newcommand{dt}{,mathrm{d}t}

      begin{document}

      begin{align*}
      Laplace[big]{f(t)}
      &= int_0^infty e^{-st} cdot f(t) dt \
      &= lim_{b rightarrow infty} int_0^b e^{-st} cdot f(t) dt \
      &= lim_{b rightarrow infty} biggl[ int_0^3 e^{-st} cdot 0 dt + int_3^b e^{-st} cdot 1 dt biggr] \
      &= lim_{b rightarrow infty} biggl[ 0 + int_3^b e^{-st} cdot 1 dt biggr] \
      &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggmvert s neq 0 biggr]_3^b
      end{align*}

      end{document}


      or just include it as a description:



      enter image description here



      begin{align*}
      % ...
      &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggr]_3^b qquad text{(where $s neq 0$)}
      end{align*}





      share|improve this answer























        up vote
        3
        down vote



        accepted







        up vote
        3
        down vote



        accepted






        Conditionals in mathematics are often expressed using a { <expr> | <cond> } format, read as <expr> given <cond>. Perhaps consider that here:



        enter image description here



        documentclass{article}

        usepackage{mathtools}
        newcommand{Laplace}{mathcal{L}laplace}
        DeclarePairedDelimiter{laplace}{[}{]}
        newcommand{dt}{,mathrm{d}t}

        begin{document}

        begin{align*}
        Laplace[big]{f(t)}
        &= int_0^infty e^{-st} cdot f(t) dt \
        &= lim_{b rightarrow infty} int_0^b e^{-st} cdot f(t) dt \
        &= lim_{b rightarrow infty} biggl[ int_0^3 e^{-st} cdot 0 dt + int_3^b e^{-st} cdot 1 dt biggr] \
        &= lim_{b rightarrow infty} biggl[ 0 + int_3^b e^{-st} cdot 1 dt biggr] \
        &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggmvert s neq 0 biggr]_3^b
        end{align*}

        end{document}


        or just include it as a description:



        enter image description here



        begin{align*}
        % ...
        &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggr]_3^b qquad text{(where $s neq 0$)}
        end{align*}





        share|improve this answer












        Conditionals in mathematics are often expressed using a { <expr> | <cond> } format, read as <expr> given <cond>. Perhaps consider that here:



        enter image description here



        documentclass{article}

        usepackage{mathtools}
        newcommand{Laplace}{mathcal{L}laplace}
        DeclarePairedDelimiter{laplace}{[}{]}
        newcommand{dt}{,mathrm{d}t}

        begin{document}

        begin{align*}
        Laplace[big]{f(t)}
        &= int_0^infty e^{-st} cdot f(t) dt \
        &= lim_{b rightarrow infty} int_0^b e^{-st} cdot f(t) dt \
        &= lim_{b rightarrow infty} biggl[ int_0^3 e^{-st} cdot 0 dt + int_3^b e^{-st} cdot 1 dt biggr] \
        &= lim_{b rightarrow infty} biggl[ 0 + int_3^b e^{-st} cdot 1 dt biggr] \
        &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggmvert s neq 0 biggr]_3^b
        end{align*}

        end{document}


        or just include it as a description:



        enter image description here



        begin{align*}
        % ...
        &= lim_{b rightarrow infty} biggl[ dfrac {e^{-st}}{-s} biggr]_3^b qquad text{(where $s neq 0$)}
        end{align*}






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 6 at 1:36









        Werner

        435k619531641




        435k619531641






























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