A function analytic in the unit disk belongs to the class Nevanlinna if and only if it is the quotient of two...











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I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it. enter image description here










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  • $F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
    – Nosrati
    Nov 16 at 18:15















up vote
0
down vote

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I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it. enter image description here










share|cite|improve this question






















  • $F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
    – Nosrati
    Nov 16 at 18:15













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0
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favorite









up vote
0
down vote

favorite











I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it. enter image description here










share|cite|improve this question













I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it. enter image description here







functional-analysis proof-explanation harmonic-functions analytic-functions






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asked Nov 16 at 17:29









Kale36

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  • $F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
    – Nosrati
    Nov 16 at 18:15


















  • $F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
    – Nosrati
    Nov 16 at 18:15
















$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15




$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15















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