Get element from json array javascript [closed]
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}
4
I have a simple Json String
[
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
I want get field Name in Data in ValueInput by Javascript.
Please help me!
javascript arrays json object
edited Mar 25 at 8:49
Jack Bashford
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – pirho, wscourge, Kristopher Ives, Bart
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
4
I have a simple Json String
[
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
I want get field Name in Data in ValueInput by Javascript.
Please help me!
javascript arrays json object
edited Mar 25 at 8:49
Jack Bashford
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – pirho, wscourge, Kristopher Ives, Bart
If this question can be reworded to fit the rules in the help center, please edit the question.
1
You can useJSON.parseto convert json to object.
– Eddie
Mar 25 at 8:44
2
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18
add a comment |
4
4
4
I have a simple Json String
[
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
I want get field Name in Data in ValueInput by Javascript.
Please help me!
javascript arrays json object
edited Mar 25 at 8:49
Jack Bashford
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
I have a simple Json String
[
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
I want get field Name in Data in ValueInput by Javascript.
Please help me!
javascript arrays json object
javascript arrays json object
edited Mar 25 at 8:49
Jack Bashford
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
edited Mar 25 at 8:49
Jack Bashford
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
edited Mar 25 at 8:49
Jack Bashford
15k31848
edited Mar 25 at 8:49
Jack Bashford
15k31848
edited Mar 25 at 8:49
Jack Bashford
15k31848
15k31848
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
asked Mar 25 at 8:42
Java Dev BeginnerJava Dev Beginner
6018
6018
closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – pirho, wscourge, Kristopher Ives, Bart
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by CertainPerformance, pirho, wscourge, Kristopher Ives, Bart Mar 25 at 17:23
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – pirho, wscourge, Kristopher Ives, Bart
If this question can be reworded to fit the rules in the help center, please edit the question.
1
You can useJSON.parseto convert json to object.
– Eddie
Mar 25 at 8:44
2
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18
add a comment |
1
You can useJSON.parseto convert json to object.
– Eddie
Mar 25 at 8:44
2
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18
1
1
You can use
JSON.parse to convert json to object.– Eddie
Mar 25 at 8:44
You can use
JSON.parse to convert json to object.– Eddie
Mar 25 at 8:44
2
2
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18
add a comment |
7 Answers
7
active
oldest
votes
4
You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.
var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
add a comment |
1
You could use JSON.parse
var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
add a comment |
0
You can use JSON.parse
JSON.parse(o[0].valueInput).data[0].name
var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))answered Mar 25 at 8:44
R3tepR3tep
8,17382962
@Deepakguptadata[0]is not a string, the array is parsed before. See the live demo before post a comment
– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the keyvalueInput
– R3tep
Mar 25 at 9:16
add a comment |
0
Use JSON.parse, and use map:
const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
add a comment |
0
You can use an array variable and the callback function of JSON.parse to get the name key & val
let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)answered Mar 25 at 8:56
brkbrk
29.8k32244
add a comment |
0
Here is a way to do it.
let originalData = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
];
let valueInput = JSON.parse(originalData[0].valueInput);
let data = valueInput.data;
console.log(data);
for (var i = 0; i < data.length; i++){
console.log(data[i].name);
}
See jsfiddle https://jsfiddle.net/3s1na4eL/3/
Let me know if there are any questions.
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
add a comment |
0
You can do:
const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
7 Answers
7
active
oldest
votes
7 Answers
7
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.
var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
add a comment |
4
You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.
var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
add a comment |
4
4
4
You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.
var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
You need to loop through the array and then parse the stringified JSON so that you can access the data array. Then simply loop that data array to get the value of each name property.
var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});var arr = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
arr.forEach((arrObj) => {
var jsonData = JSON.parse(arrObj.valueInput);
jsonData.data.forEach(({name}) => console.log(name));
});answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
answered Mar 25 at 8:45
Ankit AgarwalAnkit Agarwal
24.4k52245
24.4k52245
add a comment |
add a comment |
1
You could use JSON.parse
var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
add a comment |
1
You could use JSON.parse
var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
add a comment |
1
1
1
You could use JSON.parse
var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
You could use JSON.parse
var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});var jsonArray = [
{
assetName: 'LCT',
assetValue: '',
typeValueInput: 'select',
valueInputSelect: null,
required: true,
valueInput:
'{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}'
}
];
let name = jsonArray[0].valueInput;
name = JSON.parse(name);
name.data.forEach(value => {
console.log(value.name, value.id);
});answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
answered Mar 25 at 8:47
Loc MaiLoc Mai
4113
4113
add a comment |
add a comment |
0
You can use JSON.parse
JSON.parse(o[0].valueInput).data[0].name
var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))answered Mar 25 at 8:44
R3tepR3tep
8,17382962
@Deepakguptadata[0]is not a string, the array is parsed before. See the live demo before post a comment
– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the keyvalueInput
– R3tep
Mar 25 at 9:16
add a comment |
0
You can use JSON.parse
JSON.parse(o[0].valueInput).data[0].name
var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))answered Mar 25 at 8:44
R3tepR3tep
8,17382962
@Deepakguptadata[0]is not a string, the array is parsed before. See the live demo before post a comment
– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the keyvalueInput
– R3tep
Mar 25 at 9:16
add a comment |
0
0
0
You can use JSON.parse
JSON.parse(o[0].valueInput).data[0].name
var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))answered Mar 25 at 8:44
R3tepR3tep
8,17382962
You can use JSON.parse
JSON.parse(o[0].valueInput).data[0].name
var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))var o = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
]
console.log(JSON.parse(o[0].valueInput).data[0].name);
// To get all, use a loop
var arrO = JSON.parse(o[0].valueInput).data;
arrO.forEach((obj) => console.log(obj.name))answered Mar 25 at 8:44
R3tepR3tep
8,17382962
answered Mar 25 at 8:44
R3tepR3tep
8,17382962
answered Mar 25 at 8:44
R3tepR3tep
8,17382962
answered Mar 25 at 8:44
R3tepR3tep
8,17382962
8,17382962
@Deepakguptadata[0]is not a string, the array is parsed before. See the live demo before post a comment
– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the keyvalueInput
– R3tep
Mar 25 at 9:16
add a comment |
@Deepakguptadata[0]is not a string, the array is parsed before. See the live demo before post a comment
– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the keyvalueInput
– R3tep
Mar 25 at 9:16
@Deepakgupta
data[0] is not a string, the array is parsed before. See the live demo before post a comment– R3tep
Mar 25 at 8:51
@Deepakgupta
data[0] is not a string, the array is parsed before. See the live demo before post a comment– R3tep
Mar 25 at 8:51
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
the input value is a string, not an object, and the string is not correctly stringified.
– AZ_
Mar 25 at 9:03
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
@AZ_ The input value is not a string. Jack make some bad edit
– R3tep
Mar 25 at 9:07
1
1
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
it says I have a simple Json String not sure maybe.
– AZ_
Mar 25 at 9:15
@AZ_ Yes he have a json string into the key
valueInput– R3tep
Mar 25 at 9:16
@AZ_ Yes he have a json string into the key
valueInput– R3tep
Mar 25 at 9:16
add a comment |
0
Use JSON.parse, and use map:
const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
add a comment |
0
Use JSON.parse, and use map:
const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
add a comment |
0
0
0
Use JSON.parse, and use map:
const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
Use JSON.parse, and use map:
const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);const data = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}]
const names = JSON.parse(data[0].valueInput).data.map(({ name }) => name);
console.log(names);answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
answered Mar 25 at 8:51
Jack BashfordJack Bashford
15k31848
15k31848
add a comment |
add a comment |
0
You can use an array variable and the callback function of JSON.parse to get the name key & val
let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)answered Mar 25 at 8:56
brkbrk
29.8k32244
add a comment |
0
You can use an array variable and the callback function of JSON.parse to get the name key & val
let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)answered Mar 25 at 8:56
brkbrk
29.8k32244
add a comment |
0
0
0
You can use an array variable and the callback function of JSON.parse to get the name key & val
let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)answered Mar 25 at 8:56
brkbrk
29.8k32244
You can use an array variable and the callback function of JSON.parse to get the name key & val
let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)let dt = [{
"assetName": "LCT",
"assetValue": "",
"typeValueInput": "select",
"valueInputSelect": null,
"required": true,
"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}];
let nameArray = ;
let dlt = JSON.parse(dt[0].valueInput, function(key, val) {
if (key === 'name') {
nameArray.push(val);
}
})
console.log(nameArray)answered Mar 25 at 8:56
brkbrk
29.8k32244
answered Mar 25 at 8:56
brkbrk
29.8k32244
answered Mar 25 at 8:56
brkbrk
29.8k32244
answered Mar 25 at 8:56
brkbrk
29.8k32244
29.8k32244
add a comment |
add a comment |
0
Here is a way to do it.
let originalData = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
];
let valueInput = JSON.parse(originalData[0].valueInput);
let data = valueInput.data;
console.log(data);
for (var i = 0; i < data.length; i++){
console.log(data[i].name);
}
See jsfiddle https://jsfiddle.net/3s1na4eL/3/
Let me know if there are any questions.
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
add a comment |
0
Here is a way to do it.
let originalData = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
];
let valueInput = JSON.parse(originalData[0].valueInput);
let data = valueInput.data;
console.log(data);
for (var i = 0; i < data.length; i++){
console.log(data[i].name);
}
See jsfiddle https://jsfiddle.net/3s1na4eL/3/
Let me know if there are any questions.
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
add a comment |
0
0
0
Here is a way to do it.
let originalData = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
];
let valueInput = JSON.parse(originalData[0].valueInput);
let data = valueInput.data;
console.log(data);
for (var i = 0; i < data.length; i++){
console.log(data[i].name);
}
See jsfiddle https://jsfiddle.net/3s1na4eL/3/
Let me know if there are any questions.
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
Here is a way to do it.
let originalData = [
{
"assetName":"LCT",
"assetValue":"",
"typeValueInput":"select",
"valueInputSelect":null,
"required":true,
"valueInput":"{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"
}
];
let valueInput = JSON.parse(originalData[0].valueInput);
let data = valueInput.data;
console.log(data);
for (var i = 0; i < data.length; i++){
console.log(data[i].name);
}
See jsfiddle https://jsfiddle.net/3s1na4eL/3/
Let me know if there are any questions.
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
answered Mar 25 at 8:59
Kabelo TookaKabelo Tooka
171110
171110
add a comment |
add a comment |
0
You can do:
const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
0
You can do:
const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
add a comment |
0
0
0
You can do:
const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
You can do:
const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));const arr = [{"assetName": "LCT","assetValue": "","typeValueInput": "select","valueInputSelect": null,"required": true,"valueInput": "{"data":[{"name":"name1","id":"12"},{"name":"name2","id":"13"},{"name":"name3","id":"14"}]}"}];
arr.forEach(o => JSON.parse(o.valueInput).data.forEach(({id, name}) => console.log(id, name)));answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
edited Mar 26 at 2:39
answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
answered Mar 25 at 8:53
Yosvel QuinteroYosvel Quintero
12k42531
12k42531
add a comment |
add a comment |
1
You can use
JSON.parseto convert json to object.– Eddie
Mar 25 at 8:44
2
Why does this have seven upvotes? It does not show any effort made by the OP. What did they try? What did not work? stackoverflow.com/help/how-to-ask
– Denny
Mar 25 at 11:18